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Archy [21]
2 years ago
10

In nature amino acids exist in what type of conformation?

Chemistry
1 answer:
liberstina [14]2 years ago
7 0

Answer:

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Explanation:

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An example of an organic sedimentary rock used as fuel would be?
Naya [18.7K]
Coal
Coal is a sedimentary rock that is made from mostly plant debris. This debris is usually formed in a swampy environment and is usually mined and used for fuel! Hope this helps!
6 0
3 years ago
Complete the following analogy:
Citrus2011 [14]
The answer of the question is C. Magnetic fields
7 0
3 years ago
As you read from left to right across the periodic table atomic numbers and what by one of each element
Illusion [34]

Answer:

As we read from left to right across the periodic table atomic numbers are increased by one each of element.

Explanation:

As we move from left to right across the periodic table the atomic number is increased by one and the number of valance electron in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.

8 0
3 years ago
Which of the following DOES NOT have 2 significant
Elanso [62]

Answer:

1.001

Explanation:

The Significant Figures are 1 0 0 1, This answer has 4 Significant figures, while the other three have only 2 significant figures

7 0
2 years ago
Urea, (NH2)2CO, is a product of metabolism of proteins. An aqueous solution is 37.2% urea by mass and has a density of 1.032 g/m
Feliz [49]

Answer:

The molarity of urea in this solution is 6.39 M.

Explanation:

Molarity (M) is <em>the number of moles of solute in 1 L of solution</em>;  that is

molarity = moles of solute ÷ liters of solution

To calculate the molality, we need to know the number of moles of urea and the volume of solution in liters. We assume 100 grams of solution.

Our first step is to calculate the moles of urea in 100 grams of the solution,

using the molar mass a conversion factor. The total moles of 100g of a 37.2 percent by mass solution is

60.06 g/mol ÷ 37.2 g = 0.619 mol

Now we need to calculate the volume of 100 grams of solution, and we use density as a conversion factor.

1.032 g/mL ÷ 100 g = 96.9 mL

This solution contains 0.619 moles of urea in 96.9 mL of solution. To express it in molarity, we need to calculate the moles present in 1000 mL (1 L) of the solution.

0.619 mol/96.9 mL × 1000 mL= 6.39 M

Therefore, the molarity of the solution is 6.39 M.

4 0
3 years ago
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