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artcher [175]
3 years ago
7

Plssss helppp will mark brainliest

Chemistry
2 answers:
olchik [2.2K]3 years ago
8 0

Answer:

high melting point

Explanation:

high melting point

alexdok [17]3 years ago
7 0
I’m don’t kill me if I’m wrong but I think it’s high melting point
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Adding O2 to the reaction 6CO2 + 6H2O C6H12O6 + 6O2. WHICH WAY WILL THE REACTION SHIFT?
Oxana [17]

Answer:

The reaction will shift to the left to produce more reactants.

Explanation:

According to the Le- Chatelier principle,

At equilibrium state when stress is applied to the system, the system will behave in such a way to nullify the stress.

The equilibrium can be disturb,

By changing the concentration

By changing the volume

By changing the pressure

By changing the temperature

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Chemical reaction:

6CO₂ +  6H₂O  ⇄  C₆H₁₂O₆ + 6O₂

In this reaction the equilibrium is disturb by increasing the concentration of Product.

When the concentration of product is increased the system will proceed in backward direction in order to regain the equilibrium. Because when product concentration is high it means reaction is not on equilibrium state. As the concentration of O₂  increased the reaction proceed in backward direction to regain the equilibrium state and more reactant is formed.

4 0
3 years ago
Determine the mass of Al(C2H3O2)3 that contains 2.63 Χ 1024 atoms of oxygen.
sergejj [24]

The molecular formula of compound is Al(C_{2}H_{3}O_{2})_{3}.

Since, in 1 mole of  Al(C_{2}H_{3}O_{2})_{3} there are 6.023\times 10^{23} atoms of  Al(C_{2}H_{3}O_{2})_{3}.

Thus, according to molecular formula, in 1 mole of  Al(C_{2}H_{3}O_{2})_{3} there are 6\times 6.023\times 10^{23}=3.61\times 10^{24} atoms of oxygen atoms.

1 atom of oxygen will be present in \frac{1}{3.61\times 10^{24}} moles of Al(C_{2}H_{3}O_{2})_{3} . Thus,

2.63\times 10^{24} atoms of oxygen \rightarrow \frac{2.63\times 10^{23}}{3.61\times 10^{24}}= 0.7285 moles of Al(C_{2}H_{3}O_{2})_{3}.

Molar mass of Al(C_{2}H_{3}O_{2})_{3} is 236 g/mol, mass can be calculated as follows:

m=n\times M=0.7285 mol\times 236 g/mol=172 g

Therefore, mass of Al(C_{2}H_{3}O_{2})_{3} will be 172 g.

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3 years ago
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A dependent variable is
Anuta_ua [19.1K]

Answer:

a variable (often denoted by y) whose value depends of that of another.

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