Answer:
[N₂] = 0.032 M
[O₂] = 0.0086 M
Explanation:
Ideal Gas Law → P . V = n . R . T
We assume that the mixture of air occupies a volume of 1 L
78% N₂ → Mole fraction of N₂ = 0.78
21% O₂ → Mole fraction of O₂ = 0.21
1% another gases → Mole fraction of another gases = 0.01
In a mixture, the total pressure of the system refers to total moles of the mixture
1 atm . 1L = n . 0.082L.atm/mol.K . 298K
n = 1 L.atm / 0.082L.atm/mol.K . 298K → 0.0409 moles
We apply the mole fraction to determine the moles
N₂ moles / Total moles = 0.78 → 0.78 . 0.0409 mol = 0.032 moles N₂
O₂ moles / Total moles = 0.21 → 0.21 . 0.0409 mol = 0.0086 moles O₂
Isotopes of any given factor all incorporate the equal variety of protons, so they have the identical atomic wide variety (for example, the atomic wide variety of helium is usually 2). Isotopes of a given factor include exceptional numbers of neutrons, therefore, special isotopes have special mass numbers.
Diameter = 200pm
200pm -> mm
200pm *^-12 / 1*10^-3 = .0000002
2.0*10-7x mm = 1.0mm
Divide x on both sides
Answer:
Number of produced moles of carbondioxide is 0.113 mol.
Explanation:
Excess of sulphuric acid is present.And the sodium carbonate is completely consumed.
Molar mass of sodium carbonate = 105.99g/mol
Given mass of sodium carbonate =12 g/mol
one mole of sodium carbonate produce one mole of carbondioxide.
0.113 mole of sodium carbonate produce 0.113 mole of carbondioxide.
Therefore, 0.113 mol of carbondioxide produced in flask 7.