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xeze [42]
3 years ago
7

Any three different between of rarefaction and compression ​

Physics
1 answer:
Anna71 [15]3 years ago
4 0

Answer:

credits to the real owner of the answer I just found it here

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Why does a moving object come to a stop on a frictional surface?
ohaa [14]
It stops cause of gravitaional pull 
3 0
4 years ago
(a) A force F = (3xî + 4yĵ), where F is in newtons and x and y are in meters, acts on an object as the object moves in the x-dir
ExtremeBDS [4]

Answer:

W = 53.6648 J

Explanation:

W = ∫ F * dr

F = < 4*x i , 3*y j > Newtons

dr = < dx, 0 >

Take the dot product:

F * dr = 4* x * dx

Now replacing numeric

W = ∫ 4 * x * dx , ║ x = ( 0 m ⇒ 5.18 m )

W = ¹ / ₂ * (4 N/m) * x ²  

W = (2 N/m) * (5.18 m)²

W = 53.6648 J

8 0
4 years ago
This fossil snake and this living rat both have a structure in their skull called the quadrate bone. What best explains why both
kolbaska11 [484]

The snake and rat both share the same ancestor population that had a quadrate bone, which was inherited from an ancestor population.

<h3>What is a homo-logous structure?</h3>

A homo-logous structure is a trait that may or not have the same function but has a common evolutionary origin.

A homo-logous structure can be used to trace the evolutionary relationships between species.

Conversely, an analogous structure has the same function but it does not reflect an evolutionary origin.

Learn more about homo-logous structure here:

brainly.com/question/8405772

8 0
3 years ago
The work done by an external force to move a -6.70 μc charge from point a to point b is 1.20×10−3 j .
ASHA 777 [7]

Answer:

108.7 V

Explanation:

Two forces are acting on the particle:

- The external force, whose work is W=1.20 \cdot 10^{-3}J

- The force of the electric field, whose work is equal to the change in electric potential energy of the charge: W_e=q\Delta V

where

q is the charge

\Delta V is the potential difference

The variation of kinetic energy of the charge is equal to the sum of the work done by the two forces:

K_f - K_i = W + W_e = W+q\Delta V

and since the charge starts from rest, K_i = 0, so the formula becomes

K_f = W+q\Delta V

In this problem, we have

W=1.20 \cdot 10^{-3}J is the work done by the external force

q=-6.70 \mu C=-6.7\cdot 10^{-6}C is the charge

K_f = 4.72\cdot 10^{-4}J is the final kinetic energy

Solving the formula for \Delta V, we find

\Delta V=\frac{K_f-W}{q}=\frac{4.72\cdot 10^{-4}J-1.2\cdot 10^{-3} J}{-6.7\cdot 10^{-6}C}=108.7 V

4 0
3 years ago
Read 2 more answers
How do the conditions in tube c prevent air reaching the iron nail​
lina2011 [118]

Answer:

The conditions stop air from getting to the nail is the oil

Explanation:

8 0
3 years ago
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