Ask question

Ask question

All categories

4 years ago

12

Help !

1 answer:

Black_prince [1.1K]4 years ago

7 0

First off, you need to know the weight of the projectile, lift and drag coefficients something like a high Reynolds number is preferred, then use the gravitational constant of 9.8 meters per second squared those would be a good start to get closer to your goal

You might be interested in

Huck Finn walks at a speed of 0.70 m/s across his raft (that is, he walks perpendicular to the raft’s motion relative to the sho

ZanzabumX [31]

Answer

given,

Hunk Finn speed,v_y= 0.7 m/s

Speed of river,v_x = 1.50 m/s

Assuming the speed of the river is in x-direction.

Speed of Hunk Finn to be in y-direction.

Hunk velocity relative to river =

$x = \sqrt{v_y^2+v_x^2}$

$x = \sqrt{2.74}$

$x =1.66\ m/s$

Speed of Hunk relative to river = 1.66 m/s

direction of the boat

$\theta =tan^{-1}(\dfrac{v_y}{v_x})$

$\theta =tan^{-1}(\dfrac{0.7}{1.50})$

$\theta = 25.01^{\circ}$

Hence, angle of the raft is 24.01°

6 0

4 years ago

25% part (c) assume that d is the distance the cheetah is away from the gazelle when it reaches full speed. Derive an expression

levacccp [35]

maximum speed of cheetah is

$v_1 = v_{max}$

speed of gazelle is given as

$v_2 = v_{g}$

Now the relative speed of Cheetah with respect to Gazelle

$v_{12} = v_1 - v_2$

$v_{12} = v_{max} - v_g$

now the relative distance between Cheetah and Gazelle is given initially as "d"

now the time taken by Cheetah to catch the Gazelle is given as

$d = v_{12}* t$

so by rearranging the terms we can say

$t = \frac{d}{v_{12}}$

$t = \frac{d}{v_{max} - v_g}$

so above is the relation between all given variable

6 0

4 years ago

Conclusion for ohm law

kari74 [83]

Ohm’s Law states that electrical current is proportional to voltage and therefore inversely proportional to resistance - V = I x R

7 0

3 years ago

Which explains why light bends when it passes from air to water?

Serggg [28]

Answer: D
Key thing to keep note, is "refraction"...
Look at some experiments on YouTube, it's helps me a lot.

4 0

3 years ago

Read 2 more answers

Suppose you wanted to be able to see astronauts on the moon. what is the smallest diameter of the objective lens required to res

joja [24]

r = distance of moon from earth = 3.84 x 10⁸ m

R = size of the object on moon = 0.67 m

D = diameter of the lens = ?

$\lambda$ = wavelength of light = 550 x 10⁻⁹ m

Using the equation for Rayleigh criterion

R/r = 1.22 $\lambda$ /D

inserting the values

0.67/(3.84 x 10⁸) = 1.22 (550 x 10⁻⁹) /D

D = 384.6 m

4 0

3 years ago