Given two points (x₁,y₁) and (x₂,y₂) the midpoint would be:
M=((x₁+x₂)/2 , (y₁+y₂)/2)
In this case, the points would be: (-8,-7) and (-7,-8); therefore:
M=((-8-7)/2 , (-7-8)/2)=(-15/2,-15/2)
Answer: C.) (-15/2 , -15,2)
Answer:
a. 1/5
b. (3, 3/5)
c. 1/5x = y
Step-by-step explanation:
Remember: (x, y)
0.5 = 1/2
(1/2, 1/10) = 1/10 ÷ 1/2 = 1/10 • 2 = 1/5, you can divide y/x = constant of proportionality. 1/10 ÷ 1/2.
1 2/5 = 7/5
(7, 7/5) = 7/5 ÷ 7 = 7/5 • 1/7 = 1/5, y/x = constant of proportionality. 7/5 ÷ 7.
- a. 1/5 is the constant of proportionality
- b. (3, 3/5) because 3/5 ÷ 3 or 3/5 • 1/3 = 1/5.
- c. 1/5x = y
You can not use either of them because neither of them have a variable= to the eqaution
ex.) y= 3x+25
Answer:
1/8
Step-by-step explanation:
P(5) = 1/8
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For any sort of pyramid or cone, the volume is 1/3 of the volume of a prism with the same base and height. Since the volume of a prism/cylinder is
![V=Bh](https://tex.z-dn.net/?f=V%3DBh)
, the volume of a pyramid/cone is
![V=\frac{1}3Bh](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D3Bh)
.
In this case, our base is a circle, which has a radius of 4 cm.
The area of a circle is
![A=\pi r^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2)
where r is the radius.
![A=\pi (4)^2=\pi (4\times4)=16\pi=B](https://tex.z-dn.net/?f=A%3D%5Cpi%20%284%29%5E2%3D%5Cpi%20%284%5Ctimes4%29%3D16%5Cpi%3DB)
We now know that our base is 16π cm.
We also know that our height is 9 cm.
Let's plug these into our volume formula.
![V=\frac{1}3\times16\pi \times9](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D3%5Ctimes16%5Cpi%20%5Ctimes9)
Use 3.14 to approximate pi as the question states. 16 × 3.14 = 50.24.
![V\approx\frac{1}3\times50.24\times9](https://tex.z-dn.net/?f=V%5Capprox%5Cfrac%7B1%7D3%5Ctimes50.24%5Ctimes9)
We could punch all of that into our calculator to get the same answer, but since 1/3 of 9 is clearly 3, let's just go with that.
![V\approx3\times50.24](https://tex.z-dn.net/?f=V%5Capprox3%5Ctimes50.24)