What is the value of y so that the equation is true?

Mathematics

1 answer:

polet [3.4K]2 years ago

7 0

Answer:

I guess that You made a mistake and You wanted to solve equations $\sqrt[2]{y}$ . Then the answer is D because There is no number that gives a negative number after the square root

Step-by-step explanation:

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Please help, as soon as possible...

vodomira [7]

Answer:

1. a) Square

2. c) Rectangle

Step-by-step explanation:

1. If you cut this rectangular prism in way to be PERPENDICULAR to the base, that means you're cutting it straight down, from the top to the bottom, in a vertical line. The cross-section obtained will be just like an end of the prism, which in this case is a square. Because it's a regular rectangular prism, no matter where you cut it, as long as it's vertical, perpendicular to the base, you'll get a square due to this particular form. Technically, the answer could also be a rectangle, since a square is a rectangle.

2. you cut this rectangular prism in way to be PARALLEL to the base, that means you're cutting it straight, from the front to the back, in an horizontal line. The cross-section obtained will be just like an top of the prism, which in this case is a rectangle. Because it's a regular rectangular prism, no matter where you cut it, as long as it's an horizontal line, parallel to the base, you'll get a rectangle due to this particular form.

6 0

3 years ago

Solve the system of equations by graphing: 2x + 3y = 2 6x + 18y = 9

cluponka [151]

The answer is A: x=1/2 , y= 1/3

Solve the following system:
{2 x + 3 y = 2 | (equation 1)
{6 x + 18 y = 9 | (equation 2)

Swap equation 1 with equation 2:
{6 x + 18 y = 9 | (equation 1)
{2 x + 3 y = 2 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:
{6 x + 18 y = 9 | (equation 1)
{0 x - 3 y = -1 | (equation 2)

Divide equation 1 by 3:
{2 x + 6 y = 3 | (equation 1)
{0 x - 3 y = -1 | (equation 2)

Multiply equation 2 by -1:
{2 x + 6 y = 3 | (equation 1)
{0 x+3 y = 1 | (equation 2)

Divide equation 2 by 3:
{2 x + 6 y = 3 | (equation 1)
{0 x+y = 1/3 | (equation 2)

Subtract 6 × (equation 2) from equation 1:
{2 x+0 y = 1 | (equation 1)
v0 x+y = 1/3 | (equation 2)

Divide equation 1 by 2:
{x+0 y = 1/2 | (equation 1)
v0 x+y = 1/3 | (equation 2)

Collect results:
Answer: {x = 1/2, y = 1/3