hi,,
329.1 is the answer...
if I round off the no. nearest whole no.
then the answer is 329.
The y value has changed by 8
Answer:
0.0000
Unusual
Step-by-step explanation:
Given that a tobacco company claims that the amount of nicotine in its cigarettes is a random variable with mean 2.2 mg and standard deviation .3 mg.
i.e. population parameters are
![\mu =2.2 \\s = 0.3](https://tex.z-dn.net/?f=%5Cmu%20%3D2.2%20%5C%5Cs%20%3D%200.3)
The approximate probability that the sample meanwould have been as high or higher than 3.1
![=P(X\geq 3.1)\\=P(Z\geq \frac{3.1-2.2}{\frac{0.3}{\sqrt{100} } } )\\=P(Z\geq 30)\\](https://tex.z-dn.net/?f=%3DP%28X%5Cgeq%203.1%29%5C%5C%3DP%28Z%5Cgeq%20%5Cfrac%7B3.1-2.2%7D%7B%5Cfrac%7B0.3%7D%7B%5Csqrt%7B100%7D%20%7D%20%7D%20%29%5C%5C%3DP%28Z%5Cgeq%2030%29%5C%5C)
=0.0000
80y² - 5x²
Factorise
5(16y²-x²)
hope this helps
divide out any similar things, in this case, it is 5
put it outside the parenthesis, and leave the leftover inside the parenthesis
hope this helps