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Rashid [163]
3 years ago
15

Help please. Giving brainliest.

Mathematics
1 answer:
mash [69]3 years ago
7 0
How can i help you???
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How do I do the substitution method?
Lina20 [59]

Step-by-step explanation:

1: Solve one Equation for one of the variables

2: Substitute (plug-in) this expression into the other equation and solve

3: Resubtitue the value into the original equation to find the corresponding variable

5 0
3 years ago
Read 2 more answers
HELP BRAINISET TO WHOEVER RIGHT
Natasha_Volkova [10]

Answer:

A: 171.75

B: 170

Step-by-step explanation:

The mean (or average) can be found by...

- add all the numbers together (we will call this y)

- divide the total sum (or y) by the total amount of numbers used to add

Formula:

(x₁ + x₂ + x₃ + ... + xₙ) ÷ n

For A:

(172 + 130 + 173 + 212) ÷ 4 = 171.75

For B:

(136 + 184 + 168 + 192) ÷ 4 = 170

8 0
3 years ago
Pls help type the correct answer in each box:
grigory [225]

Answer:

Switch x and y.

Solve for x.

Function can be written as x²+4.

and last one will be 4.

;-)

Step-by-step explanation:

6 0
3 years ago
How do I make this into a solid number<br><br><img src="https://tex.z-dn.net/?f=3%20%5Cfrac%7B5%7D%7B6%7D%20-%20%20-%201%5Cfrac%
Effectus [21]

Answer:

Basic Of Algebra. Basics of Algebra cover the simple operation of mathematics like addition, subtraction, multiplication, and division involving both constant as well as variables. For example, x+10 = 0. This introduces an important algebraic concept known as equations. Step-by-step explanation:

6 0
3 years ago
Two positive integers have a sum of 10 and a product of 21. What are the integers?
lara [203]

Answer:

<h2>3 and 7</h2>

Step-by-step explanation:

x,y-\text{positive integers}\\\\\text{The system of equations:}\\\\\left\{\begin{array}{ccc}x+y=10&\text{subtract}\ y\ \text{from both sides}\\xy=21\end{array}\right\\\\\left\{\begin{array}{ccc}x=10-y&(1)\\xy=21&(2)\end{array}\right\\\\\text{substitute (1) to (2):}\\\\(10-y)(y)=21\qquad\text{use the distributive property}\ a(b-c)=ab-ac\\\\10y-y^2=21\qquad\text{subtract 21 from both sides}\\\\-y^2+10y-21=0\qquad\text{change the signs}\\\\y^2-10y+21=0\\\\y^2-3y-7y+21=0\\\\y(y-3)-7(y-3)=0

(y-3)(y-7)=0\iff y-3=0\ \vee\ y-7=0\\\\y-3=0\qquad\text{add 3 to both sides}\\\\y=3\\\\y-7=0\qquad\text{add 7 to both sides}\\\\y=7\\\\\text{Put the value of}\ y\ \text{to (1):}\\\\x=10-3=7\ or\ x=10-7=3

7 0
3 years ago
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