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Rashid [163]
3 years ago
15

Help please. Giving brainliest.

Mathematics
1 answer:
mash [69]3 years ago
7 0
How can i help you???
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What is the answer please im in a hery
antiseptic1488 [7]

Answer:

Factor 12a + 6b : 6(2a + b)

Step-by-step explanation:

12a+6b

Rewrite 12 as 2 * 6:

=2\cdot \:6a+6b

Factor out common term 6:

=6\left(2a+b\right)

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, Have a good day! =)

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No.

Step-by-step explanation:

If you insert 1 as x, you get 1 \geq 6. This is not true.

Hope it helps!

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Which of the following is least likely to be a warning sign that one's debt is at a critical point?
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4 1
3 years ago
How do I solve a given right triangle to find Cos, Sin, and Tan. How do I solve for a missing adjacent side? (For Example: Imagi
Sphinxa [80]

The steps to find cos, sin, and tan and missing adjacent side of a given right angle triangle is explained.

<u>Solution:</u>

Given, a right triangle with A, B, and C.  

Opposite side = 70 inches  

Hypotenuse = 12 feet = 12 \times 12 inches = 144 inches

Adjacent side = "x" inches.  

We are not given angle, so we have to use the hypotenuse theorem

Hypotenuse theorem  means square of the length of the hypotenuse is equal to the sum of squares of the lengths of other two sides of the right-angled triangle.

\text { hypotenuse }^{2}=(\text { opposite side })^{2}+(\text { adjacent side })^{2}

Substituting the values we get,

\begin{array}{l}{\rightarrow 144^{2}=70^{2}+x^{2}} \\\\ {\rightarrow x^{2}=20736-4900} \\\\ {\rightarrow x^{2}=15836} \\\\ {\rightarrow x=\sqrt{15836}} \\\\ {\rightarrow x=125.841}\end{array}

So, the adjacent side value is 125.8 inches approximately.

Hence the steps to find adjacent side is shown above

Now let us find cos, sin and tan

\begin{aligned} \sin \theta &=\frac{\text {opposite side}}{\text {hypotenuse}} \\\\ \cos \theta &=\frac{\text {adjacent side}}{\text {hypotenuse}} \\\\ \tan \theta &=\frac{\text {opposite side}}{\text {adjacent side}} \end{aligned}

By substituting the required values, we can find cos, sin and tan

\begin{array}{l}{\sin \theta=\frac{70}{144}=\frac{35}{122}} \\\\ {\cos \theta=\frac{125.8}{144}=\frac{62.9}{122}} \\\\ {\tan \theta=\frac{70}{125.8}=\frac{35}{62.9}}\end{array}

5 0
3 years ago
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