Open Response Abigail surveyed

Redondear a 4 decimales 35614326

Verizon [17]

Can you translate i can help you better

4 0

3 years ago

1.

GREYUIT [131]

People who picked up vanilla cupcakes = 80% x 53

<u> 80% x 53 = 0.8 x 53 = 42 people </u>(nearest whole number)

42 people picked vanilla cupcakes

Volume of a sphere = 4/3πr³

<u>4/3πr³ = 4/3π(7)³ = 1436.8 cm³</u>

The volume of the sphere is 1436.8 cm³

3 0

3 years ago

Read 2 more answers

A number z, when rounded to the nearest whole, is equal to 70. Find the upper and lower bound of x

rusak2 [61]

Answer:

A quick way to calculate upper and lower bands is to halve the degree of accuracy specified, then add this to the rounded value for the upper bound and subtract it from the rounded value for the lower bound.

4 0

2 years ago

HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME

Kryger [21]

Answer:

1)

Given the triangle RST with Coordinates R(2,1), S(2, -2) and T(-1 , -2).

A dilation is a transformation which produces an image that is the same shape as original one, but is different size.

Since, the scale factor $\frac{5}{3}$ is greater than 1, the image is enlargement or a stretch.

Now, draw the dilation image of the triangle RST with center (2,-2) and scale factor $\frac{5}{3}$

Since, the center of dilation at S(2,-2) is not at the origin, so the point S and its image $S{}'$ are same.

Now, the distances from the center of the dilation at point S to the other points R and T.

The dilation image will be $\frac{5}{3}$ of each of these distances,

$SR=3$ , so $S{}'R{}'$ =5 ;

$ST=3$ , so $S{}'T{}'=5$

Now, draw the image of RST i.e R'S'T'

Since, $RT=3\sqrt{2}$ [By using hypotenuse of right angle triangle] and $R{}'T{}'=5\sqrt{2}$ .

2)

(a)

Disagree with the given statement.

Side Angle Side postulate (SAS) states that:

If two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle then these two triangles are congruent.

Given: B is the midpoint of $\overline{AC}$ i.e $\overline{AB}\cong \overline{BC}$

In the triangle ABD and triangle CBD, we have

$\overline{AB}\cong \overline{BC}$ (SIDE) [Given]

$\overline{BD}\cong \overline{BD}$ (SIDE) [Reflexive post]

Since, there is no included angle in these triangles.

∴ $\Delta ABD$ is not congruent to $\Delta CBD$ .

Therefore, these triangles does not follow the SAS congruence postulates.

(b)

SSS(SIDE-SIDE-SIDE) states that if three sides of one triangle are congruent to three sides of another triangle, then the triangles are congruent.

Since it is also given that $\overline{AD}\cong \overline{CD}$ .