1) a = 2, b= 3, c=2,
2) x^2 -2x-4 (a = 1, b=-2, c =-4)
3) x^2+x+3 (a,b = 1, c = 3)
4) 7x^2+8x-4 (a=7, b=8, c=-4)
Refer to the figure shown below.
The coordinates of point m are (2,5).
Let (x,y) = the coordinates of pont n.
Because mn = 4, use the Pythagorean theorem to obtain
(x - 2)² + (y - 5)² = 4²
This represents a circle with center at (2,5) and radus = 4.
Answer:
Possible coordinates for n lie on the circle (x-2)² + (y-5)² = 16.
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