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Alla [95]
2 years ago
15

Bozena is an ecologist who studies the change in the tiger population of Siberia over time. The relationship between the elapsed

time t tt, in years, since Bozena started studying the population, and the number of tigers, N ( t ) N(t)N, left parenthesis, t, right parenthesis, is modeled by the following function: N(t)=537⋅(0.35)t2 Complete the following sentence about the rate of change in the tiger population. The population of tigers loses 65 % 65%65, percent of its size every years.
Mathematics
1 answer:
klio [65]2 years ago
6 0

Answer:

every 2 years

Step-by-step explanation:

since it is t/2 for the exponent - thas the answer on khan

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MatroZZZ [7]

Answer:

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Step-by-step explanation:

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2 years ago
A piece of wire is 8/9 meter long broke into two pieces. One piece is 2/3 meter long. How long is the other?
Genrish500 [490]

Answer:

<h2><em><u>2/9 is the answer.</u></em></h2>

Step-by-step explanation:

<em><u>1. First, make an equation.</u></em>

<em><u>Given:</u></em>

8/9 = length of wire

2/3 = length of a part of the wire

E = 8/9-2/3

<em><u>Unknown:</u></em>

Second part of wire

<em><u>2. Make the numbers have equal denominators</u></em>

2/3 * 3/3

= 6/9

<em><u>3. Solve</u></em>

8/9 - 6/9

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Hope this helped,

Kavitha

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2 years ago
I need this please help ​
Korolek [52]

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30

Step-by-step explanation:

Add all of them

5 0
3 years ago
MULTIPLE CHOICE GEOMOTRY QUESTIOON
rosijanka [135]

Answer: D

Step-by-step explanation: Im vv sure, is this a test?

7 0
2 years ago
What is the average rate of change of the function
Reptile [31]

Answer:

Average rate of change =-35.7084

Step-by-step explanation:

Given function is f(x)=480(0.3)^x and we need to find average rate of change of the function from x=1\ to\ x=5.

Average rate of change =\frac{f(b)-f(a)}{b-a}

So,

here\ b=5\ and\ a=1\\f(5)=480(0.3)^5\\=480\times0.00243=1.1664\\and\\f(1)=480(0.3)^1\\=480\times0.3=144

Average rate of change

=\frac{f(b)-f(a)}{b-a}\\\\=\frac{f(5)-f(1)}{5-1}\\\\=\frac{1.1664-144}{5-1}\\\\=\frac{-142.8336}{4}= -35.7084

Hence, average rate of change of the function f(x)=480(0.3)^x over the intervel x=1\ to\ x=5 is =-35.7084.  

5 0
3 years ago
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