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Pie
3 years ago
12

Suppose Earth's gravitational force were decreased by half. How would this change affect a game of basketball? Write a paragraph

explaining how the motion of the players and the ball would be different.
Physics
2 answers:
hammer [34]3 years ago
6 0
Due to the decrease in the gravitational force, it will take longer time for ball to reach the ground while dribbling. Moreover, the hang time of players will also be longer. This means that the players will stay on air longer and will be able to jump higher. 
viktelen [127]3 years ago
5 0
They would be able to jump higher with less effort the ball would weigh less meaning it could be dribbled with little to no effort there would also be the fact that your running would be effected.your legs would come off the ground if only for an inch or two allowing you to travel faster but with less control
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Non-metals can form cations when combined with metals and anions when combined with other non-metals.
exis [7]
Well i think it is false caus ebunch of products these day have metals incorparded in the product
4 0
3 years ago
Read 2 more answers
In the "before" part of Fig. 9-60, car A (mass 1100 kg) is stopped at a traffic light when it is rear-ended by car B (mass 1400
liq [111]

Complete Question:

In the "before" part of Fig. 9-60, car A (mass 1100 kg) is stopped at a traffic light when it is rear-ended by car B (mass 1400 kg). Both cars then slide with locked wheels until the frictional force from the slick road (with a low ?k of 0.15) stops them, at distances dA = 6.1 m and dB = 4.4 m. What are the speeds of (a) car A and (b) car B at the start of the sliding, just after the collision? (c) Assuming that linear momentum is conserved during the collision, find the speed of car B just before the collision.

Answer:

a) Speed of car A at the start of sliding = 4.23 m/s

b) speed of car B at the start of sliding = 3.957 m/s

c) Speed of car B before the collision = 7.28 m/s

Explanation:

NB: The figure is not provided but all the parameters needed to solve the question have been given.

Let the frictional force acting on car A, f_{ra} = \mu mg\\............(1)

Since frictional force is a type of force, we are safe to say f_{ra} = ma.......(2)

Equating (1) and (2)

ma = \mu mg\\a = \mu g\\\mu = 0.15\\a = 0.15 * 9.8 = 1.47 m/s^{2}

a) Speed of A at the start of the sliding

d_{A} = 6.1 m\\Speed of A at the start of sliding, v_{A} = \sqrt{2ad_{A} }\\ v_{A} = \sqrt{2*1.47*6.1 } \\v_{A} = \sqrt{17.934 } \\v_{A} = 4.23 m/s

b) Speed of B at the start of the sliding

d_{A} = 4.4 m\\Speed of A at the start of sliding, v_{B} = \sqrt{2ad_{B} }\\ v_{B} = \sqrt{2*1.47*4.4 } \\v_{B} = \sqrt{12.936 } \\v_{B} = 3.957 m/s

Let the speed of car B before collision = v_{B1}

Momentum of car B before collision = m_{B} v_{B1}

Momentum after collision = m_{A} v_{A} + m_{B} v_{B2}

Applying the law of conservation of momentum:

m_{B} v_{B1}  = m_{A} v_{A} +m_{B} v_{B2}

m_{A} = 1100 kg\\m_{B} = 1400 kg

(1400*v_{B1} ) = (1100 * 4.23) + ( 1400 * 3.957)\\(1400*v_{B1} ) = 10192.8\\v_{B1} = 10192.8/1400\\v_{B1 = 7.28 m/s

3 0
4 years ago
Read 2 more answers
An electron is accelerated from rest through a potential difference. After acceleration the electron has a de Broglie wavelength
Vladimir [108]

Answer:

3x10⁴v

Explanation:

Using

Wavelength= h/ √(2m.Ke)

880nm = 6.6E-34/√ 2.9.1E-31 x me

Ke= 6.6E-34/880nm x 18.2E -31.

5.6E-27/18.2E-31

= 3 x 10⁴ Volts

4 0
3 years ago
The convection zone is the outer most layer of the suns blank hot gases rise and then blank hear the loops form by singing cool
lora16 [44]

Answer:

Explanation:

The sun is made up of 6 parts. Namely:

  1. The core
  2. The radiation zone
  3. The convection zone
  4. The photosphere
  5. The chromosphere and
  6. The corona

The convection area is just above the radiation zone. As materials from the suns core are heated, they rise above the radiation zone towards the EDGE of the convection area then sinks back again into the radiative zone for more heat.

The radiative zone is 12.6 million Fahrenheit hot and is just above the core.

The core of the son is not solid but plasma whose motion is like gas. Its temperature stands at 48 million Fahrenheit

Cheers

5 0
3 years ago
Suppose a clay model of a koala bear has a mass of 0.205 kg and slides on ice at a speed of 0.720 m/s. It runs into another clay
Westkost [7]

Answer:

Final velocity, v = 0.28 m/s

Explanation:

Given that,

Mass of the model, m_1=0.205\ kg

Speed of the model, u_1=0.72\ m/s

Mass of another model, m_2=0.32\ kg

Initial speed of another model, u_2=0

To find,

Final velocity

Solution,

Let V is the final velocity. As both being soft clay, they naturally stick together. It is a case of inelastic collision. Using the conservation of linear momentum to find it as :

m_1u_1+m_2u_2=(m_1+m_2)V

V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}

V=\dfrac{0.205\times 0.72+0.32\times 0}{(0.205+0.32)}

V = 0.28 m/s

So, their final velocity is 0.28 m/s. Hence, this is the required solution.

6 0
3 years ago
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