Answer: A.True
Explanation: simply put the magnitude of the speed is a function of Distance while the magnitude of velocity is a function of Displacement. Displacement is the average Distance moved in different directions which will be smaller in magnitude compared to the Total Distance used the calculating the magnitude of speed.
Answer:
Explanation:
Total momentum of the system before the collision
.5 x 3 - 1.5 x 1.5 = -0.75 kg m/s towards the left
If v be the velocity of the stuck pucks
momentum after the collision = 2 v
Applying conservation of momentum
2 v = - .75
v = - .375 m /s
Let after the collision v be the velocity of .5 kg puck
total momentum after the collision
.5 v + 1.5 x .231 = .5v +.3465
Applying conservation of momentum law
.5 v +.3465 = - .75
v = - 2.193 m/s
2 ) To verify whether the collision is elastic or not , we verify whether the kinetic energy is conserved or not.
Kinetic energy before the collision
= 2.25 + 1.6875
=3.9375 J
kinetic energy after the collision
= .04 + 1.2 =1.24 J
So kinetic energy is not conserved . Hence collision is not elastic.
3 ) Change in the momentum of .5 kg
1.5 - (-1.0965 )
= 2.5965
Average force applied = change in momentum / time
= 2.5965 / 25 x 10⁻³
= 103.86 N
The reading of the balance if ,
I ) If the elevator is moving with a steady speed = 50 N
II ) If the elevator is moving upwards with acceleration of 0.2 m / s² = 51 N
T = m g + m a
T = Force
m = Mass
g = Acceleration due to gravity
a = Acceleration
m = 5 kg
g = 10 m / s²
I ) If the elevator is moving with a steady speed,
At steady speed, a = 0
T = ( 5 * 10 ) + ( 5 * 0 )
T = 50 N
II ) If the elevator is moving upwards with acceleration of 0.2 m / s²,
a = 0.2 m / s²
T = ( 5 * 10 ) + ( 5 * 0.2 )
T = 50 + 1
T = 51 N
Therefore, the reading of the balance if ,
I ) If the elevator is moving with a steady speed = 50 N
II ) If the elevator is moving upwards with acceleration of 0.2 m / s² = 51 N
To know more about reading on a spring balance
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To solve this problem it is only necessary to apply the kinematic equations of angular motion description, for this purpose we know by definition that,
Where,
Angular Displacement
Angular Acceleration
Angular velocity
Initial angular displacement
For this case we have neither angular velocity nor initial angular displacement, then
Re-arrange for 
Replacing our values,
Therefore the ANgular acceleration of the mass is 
