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Vanyuwa [196]
3 years ago
8

A machine does 1500 joules of work in 30 second What is the power of the machine

Physics
1 answer:
lesya [120]3 years ago
8 0
This is simple as power in watts is equal to joules per second so we can do 1500 joules divided by 30 seconds which equals 50 watts
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In lightning storms, the potential difference between the Earth and the bottom of the thunderclouds can be as high as 350MV . Th
AleksAgata [21]

Complete Question

In lightning storms, the potential difference between the Earth and the bottom of the thunderclouds can be as high as 350 MV (35,000,000 V). The bottoms of the thunderclouds are typically 1500 m above the earth, and can have an area of 120 km^2. Modeling the earth/cloud system as a huge capacitor, calculate

a. the capacitance of the earth-cloud system

b. the charge stored in the "capacitor"

c. the energy stored in the capacitor

Answer:

a

 C =  7.08 *10^{-7} \  F

b

  Q =  24.78 \  C

c

 E =433650000 \ J

Explanation:

From the question we are told that

The potential difference is  V  =  35000000 V

The distance of the bottom of the thunderstorm from the earth is  d = 1500 m

The area is  A =  120 \  km^2 =  120 *10^{6} \  m^2

Generally the capacitance of the earth cloud system is mathematically represented as

         C =  \epsilon_o *  \frac{A}{d}

 Here \epsilon_o is the permitivity of free space with as value \epsilon_o =  8.85 *10^{-12} \  C/(V\cdot m)

So

     C =  8.85*10^{-12} *  \frac{120*10^{6}}{1500}

=>  C =  7.08 *10^{-7} \  F

Generally the charge stored in the capacitor (earth-cloud system) is mathematically represented as

       Q =  C  *  V

=>    Q =  7.08 *10^{-7}  *   35000000

=>    Q =  24.78 \  C

Generally the energy stored in the capacitor is mathematically represented as

       E = \frac{1}{2}  * Q *  V

=>    E = \frac{1}{2}  *   24.78 *  35000000

=>    E =433650000 \ J

   

8 0
3 years ago
sketch a graph of position vs. time for a person starting 0.4 m away and standing still. Include an explanation of your predicti
Korvikt [17]

Answer:

Straight line parallel to time axis.

Explanation:

The slope of the position time graph gives the velocity.

As the man is still, that means the velocity is zero. So, the slope of the graph is zero. It is a straight line parallel to time axis.

5 0
3 years ago
calculate the electric field strength between two parallel plates separated by 0.50 cm, across which is a potential of 12 volts.
Alexxandr [17]
Formula for Electric Field strength , E =  V/d

where V = Voltage in volts, and d = distance of separation in meters.

d = 0.5 cm = 0.005 m,    V = 12 V

E = V/d =  12 / 0.005

E = 2400

Electric Field Strength = 2400 Volts/meter 
3 0
3 years ago
(b) The cylinder shown in figure 2 is fitted with a freely sliding piston containing an ideal gas of mass 13g and volume 1.0×10⁴
nekit [7.7K]

Answer:

22600 cm³ (3 s.f.)

Explanation:

Please see the attached picture for the full solution.

6 0
3 years ago
Two protons are aimed directly toward each other by a cyclotron accelerator with speeds of 1200 km/s , measured relative to the
Radda [10]

Answer:

The maximum electrical force is 2.512\times10^{-2}\ N.

Explanation:

Given that,

Speed of cyclotron = 1200 km/s

Initially the two protons are having kinetic energy given by

\dfrac{1}{2}mv^2=\dfrac{1}{2}mv^2

When they come to the closest distance the total kinetic energy is converts into potential energy given by

Using conservation of energy

mv^2=\dfrac{kq^2}{r}

r=\dfrac{kq^2}{mv^2}

Put the value into the formula

r=\dfrac{8.99\times10^{9}\times(1.6\times10^{-19})^2}{1.67\times10^{-27}\times(1200\times10^{3})^2}

r=9.57\times10^{-14}\ m

We need to calculate the maximum electrical force

Using formula of force

F=\dfrac{kq^2}{r^2}

F=\dfrac{8.99\times10^{9}\times(1.6\times10^{-19})^2}{(9.57\times10^{-14})^2}

F=2.512\times10^{-2}\ N

Hence, The maximum electrical force is 2.512\times10^{-2}\ N.

8 0
3 years ago
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