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Schach [20]
3 years ago
9

A 48.0-kg astronaut is in space, far from any objects that would exert a significant gravitational force on him. He would like t

o move toward his spaceship, but his jet pack is not functioning. He throws a 0.720-kg socket wrench with a velocity of 5.00 m/s in a direction away from the ship. After 0.500 s, he throws a 0.800-kg spanner in the same direction with a speed of 8.00 m/s. After another 9.90 s, he throws a mallet with a speed of 6.00 m/s in the same direction. The mallet has a mass of 1.20 kg. How fast is the astronaut moving after he throws the mallet?(assume all speeds are relative to the spaceship). m/s
Physics
1 answer:
marusya05 [52]3 years ago
5 0

Answer:

The astronaut is moving at a speed of 0.36m/s

Explanation:

Speed here corresponds to velocity

The astronaut's mass = 48kg

velocity of astronaut = ?

mass of socket = 0.72kg

velocity of socket = 5m/s

mass of the spanner = 0.8kg

velocity of spanner = 8m/s

change in time = 0.05 -0 = 0.05sec

mass of the mallet = 1.2kg

velocity of mallet = 6m/s

change in time = 9.9 -0 = 9.9sec

To find the astronaut velocity, we would calculate the total momentum which is the astronaut.

∑momentum (M) = ∑astronaut momentum

∑M = ∑astronaut M

∑astronaut M = M of socket + M of spanner + M of mallet

momentum = mass × velocity

(mass × velocity)of astronaut = (0.72×5) + (0.8×8) + (1.2×6)

48 × velocity of astronaut= 3.6 + 6.4 + 7.2

48 × velocity of astronaut= 17.2

velocity of astronaut = 17.2/48

velocity of astronaut = 0.36m/s

The astronaut is moving at a speed of 0.36m/s

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Viefleur [7K]

Answer:

u = 18 cm

Explanation:

given,

radius of curvature = 60 cm

magnification of mirror = 2.5

distance of object  = ?

R = 2 f

f = R/2

f = 60/2 = 30 cm

m = -\dfrac{v}{u}

2.5 = -\dfrac{v}{u}

v = -2.5 u

now,

Using mirror formula

\dfrac{1}{f} = \dfrac{1}{v} + \dfrac{1}{u}

\dfrac{1}{30} = \dfrac{1}{-2.5u} + \dfrac{1}{u}

\dfrac{1}{30} = \dfrac{0.6}{u}

u = 0.6 x 30

u = 18 cm

distance of object be equal to u = 18 cm

6 0
3 years ago
Why should people pay attention to scientists when making decisions? A)scientist are the smartest people B) Scientist make up fa
MrRa [10]

Answer:

C) scientist use experiments to test their ideas

3 0
3 years ago
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An internal combustion engine uses fuel, of energy content 44.4 MJ/kg, at a rate of 5 kg/h. If the efficiency is 28%, determine
Fudgin [204]
Efficiency =  Power Output / Power Input

Power Input = Rate of Energy input = 44.4 MJ/kg * 5 kg/h

 = 222 MJ/h

But 1 hour = 3600seconds

222 MJ/h = 222 MJ/3600s =  0.061667 MW              J/s = Watts

Power input = 0.061667 MW = 61 667 W

From  Efficiency =  Power Output / Power Input

   28% =  Power Output / 61667

   Power Output = 0.28 * 61667

   Power Output = 17266.76 W
 
  Power Output = 17 267 W

 Rate of heat Rejection = Power input - Power output

                                        = 61667 - 17267 = 44400 W

Rate of heat Rejection = 44 400 W.


C- Copyright.
5 0
3 years ago
A toy car accelerates at a constant rate from rest to a speed of 4 m/s in a time of 0.55 s. What was the magnitude of the accele
Korvikt [17]
  • initial velocity=u=0m/s
  • Final velocity=v=4m/s
  • Time=t=0.5s

\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \sf\longmapsto Acceleration=\dfrac{4-0}{0.5}

\\ \sf\longmapsto Acceleration=\dfrac{4}{0.5}

\\ \sf\longmapsto Acceleration=8m/s^2

3 0
3 years ago
A person's prescription for bifocals is -0.25 diopter for distant vision and +2.50 diopters for near vision, the near vision bei
Darina [25.2K]

Answer:

net power is + 2.25 D

Explanation:

Given data

distance vision = -0.25 D

near vision = + 2.50 D

to find out

net power

solution

we have given a person lens power for near is - 0.25 diopter and lens power for near power is  +2.50 diopter so

net power is sum of both the power vision

so

net power = distance + near power

put both value we get net power

net power = ( -0.25 D) + ( + 2.50 D)

net power = + 2.25 D

so net power is + 2.25 D

6 0
3 years ago
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