Answer
given,
time interval = 11.3 s
a) initial velocity, vi = 15 m/s
final velocity, v_f = -5.30 m/s
a = -1.79 m/s²
the direction is along left side
b) initial velocity, vi = -5.30 m/s
final velocity, v_f = -15 m/s
a = -0.858 m/s²
the direction is along left side
c) initial velocity, vi = 15 m/s
final velocity, v_f = -15 m/s
a = -2.65 m/s²
the direction is along left side
Answer:
14112 J
Explanation:
When the 72 Kg mass explodes into two, one mass is twice the other so 72/3=24 Kg
M1= 24 kg, M2= 72-24=48 kg
From law of conservation of linear momentum, the sum of initial and final momentum are equal. p=mv where p is momentum, m is mass and v is velocity. Fir this case, since the less massive piece stops, its final velocity is zero.
72*28=48v2
V2=72*28/48=42 m/s
Difference between initial and final kinetic energy will be
Therefore, from observers reference, kinetic energy of 14112 J is added
Answer:
a) Ra = 0.517 Ω
Rb = 0.032 Ω
Rc = 0.129 Ω
b) Ia = 5.8A
Ib = 93.75A
Ic = 23.2 A
Explanation:
a) The resistance is equal to:
Resistance for case a:
Where
p = 1.5x10⁻²Ωm
L0 = 5.8 cm = 0.058 m
Resistance for case b:
Resistance for case c:
b) The current is equal to:
Current for case a:
Current for case b:
Current for case c:
Answer:
The requested distance is 4320 meters
Explanation:
We can use the formula for velocity in this movement at constant velocity (v), which is defined as the quotient between the distance covered divided the time it took:
Since we know the velocity and the time, we can solve for the distance: