Question

Help plz:)))I’ll mark u Brainliest

Answer 1

$\frac{245 g SO2 }{} \frac{1 mol SO2 }{64.07 g SO2} \frac{1 mol H2SO3}{1 mol SO2 } \frac{82.09 g H2SO3}{1 mol H2SO3} =314 g H2SO3$

Step-by-step explanation:

2) What mass of Sulfurous acid is produced, when 245g of Sulfur Dioxide is

reacted with water?  

H2O  +  SO2  →   H2SO3

               ↓                ↑  

              mol   →     mol

          SO2           H2SO3

\frac{245 g SO2 }{} \frac{1 mol SO2 }{64.07 g SO2} \frac{1 mol H2SO3}{1 mol SO2 } \frac{82.09 g H2SO3}{1 mol H2SO3} =314 g H2SO3