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krek1111 [17]
3 years ago
5

What is the formula for silicon tetrabromide?

Chemistry
2 answers:
Kaylis [27]3 years ago
7 0

Answer:

SiBr4

<em>hope this helps!</em>

bogdanovich [222]3 years ago
5 0

Answer:

SiBr4

Explanation:

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Butanoic acid + 1-pentanol
lutik1710 [3]

Answer: X is an Esther

Explanation: alcohol and carboxylate acid forms esters

7 0
2 years ago
Name the bonds found between amino acids in a polypeptide chain
Mekhanik [1.2K]

Answer:

<em><u>Primary Structure: Amino Acids Are Linked by Peptide Bonds to Form Polypeptide Chains. Proteins are linear polymers formed by linking the α-carboxyl group of one amino acid to the α-amino group of another amino acid with a peptide bond (also called an amide bond).</u></em>

Explanation:

<em><u>hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u> you</u></em>

8 0
2 years ago
If I add 475mL of water to 75.0mL of a 0.315M NaOH solution, what will the molarity of the diluted solution be?
pantera1 [17]
Answer is: <span>the molarity of the diluted solution 0,043 M.
</span>V(NaOH) = 75 mL ÷ 1000 mL/L = 0,075 L.
c(NaOH) = 0,315 M = 0,315 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,075 L · 0,315 mol/L.
n(NaOH) = 0,023625 mol.
V(solution) = 0,475 L + 0,75 L.
c(solution) = 0,023625 mol ÷ 0,550 L.
c(solution) = 0,043 mol/L.
5 0
3 years ago
A 1.50 L buffer solution is 0.250 M in HF and 0.250 M in NaF. Calculate the pH of the solution after the addition of 0.100 moles
alexgriva [62]

Answer : The pH of the solution is, 3.41

Explanation :

First we have to calculate the moles of HF.

\text{Moles of HF}=\text{Concentration of HF}\times \text{Volume of solution}

\text{Moles of HF}=0.250M\times 1.50L=0.375mol

Now we have to calculate the value of pK_a.

The expression used for the calculation of pK_a is,

pK_a=-\log (K_a)

Now put the value of K_a in this expression, we get:

pK_a=-\log (6.8\times 10^{-4})

pK_a=4-\log (6.8)

pK_a=3.17

The reaction will be:

                             HF+OH^-\rightleftharpoons F^-+H_2O

Initial moles     0.375     0.100   0.375

At eqm.   (0.375-0.100)      0     (0.375+0.100)

                     = 0.275                    = 0.475

Now we have to calculate the pH of solution.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

pH=pK_a+\log \frac{[F^-]}{[HF]}

Now put all the given values in this expression, we get:

pH=3.17+\log [\frac{(\frac{0.475}{1.50})}{(\frac{0.275}{1.50})}]

pH=3.41

Thus, the pH of the solution is, 3.41

8 0
3 years ago
Determine the quantity of each atom in a compound
trasher [3.6K]
1. 5 atoms
2. 5 atoms
3. 11 atoms
4. 5 atoms
5. 18 atoms
7 0
2 years ago
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