Which of the following correctly describe insulin and glucagon? select all that apply.

Chemistry

1 answer:

Shkiper50 [21]3 years ago

6 0

The correct answers are 1 and 4.
1. Both are hormones that control glucose production and storage in the body.
2. Insulin and glucagon have opposite effects on blood glucose level.

Both hormones are secreted by the pancreas. Pancreas has 2 cells as alpha and beta. alpha cells produce glucagon and beta cell produce insulin. Insulin is responsible for decreasing blood glucose level and glucagon is responsible for increasing blood glucose level. Hence, both hormones have opposite effects on blood glucose level and they help to maintain blood glucose level.

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Which type of rock is most likely to form because of high heat and pressure?

expeople1 [14]

Answer:

Metamorphic Rock

Explanation:

Metamorphic rocks are formed because of high heat and pressure . Metamorphic rocks form from heat and pressure changing the original or parent rock into a completely new rock. The parent rock can be either sedimentary, igneous, or even another metamorphic rock

6 0

2 years ago

Read 2 more answers

Suppose that 0.48 g of water at 25 ∘ C condenses on the surface of a 55- g block of aluminum that is initially at 25 ∘ C . If th

mamaluj [8]

Answer:

$49^oC$

Explanation:

At $25^oC$ , the heat of vaporization of water is given by:

$\Delta H^o_{vap} = 43988 J/mol\cdot \frac{1 mol}{18.016 g} = 2441.6 J/g$

The water here condenses and gives off heat given by the product between its mass and the heat of vaporization:

$Q_1 = \Delta H^o_{vap} m_w$

The block of aluminum absorbs heat given by the product of its specific heat capacity, mass and the change in temperature:

$Q_2 = c_{Al}m_{Al}(t_f - t_i)$

According to the law of energy conservation, the heat lost is equal to the heat gained:

$Q_1 = Q_2$ or:

$\Delta H^o_{vap} m_w = c_{Al}m_{Al}(t_f - t_i)$

Rearrange for the final temperature:

$\Delta H^o_{vap} m_w = c_{Al}m_{Al}t_f - c_{Al}m_{Al}t_i$

We obtain:

$\Delta H^o_{vap} m_w + c_{Al}m_{Al}t_i = c_{Al}m_{Al}t_f$

Then:

$t_f = \frac{\Delta H^o_{vap} m_w + c_{Al}m_{Al}t_i}{c_{Al}m_{Al}} = \frac{2441.6 J/g\cdot 0.48 g + 0.903 \frac{J}{g^oC}\cdot 55 g\cdot 25^oC}{0.903 \frac{J}{g^oC}\cdot 55 g} = 49^oC$