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xeze [42]
3 years ago
6

How to find the number of atoms present in 22g of co2​

Chemistry
1 answer:
Vanyuwa [196]3 years ago
3 0

Answer:

22g of  2

C

O

2

have  3.011×1023

3.011

×

10

23

  2

C

O

2

molecules.

Explanation:

Hope this helps! ^^

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PLEASE HELP ME!!
Mama L [17]

Answer:

A

Explanation:

3 CARBON ATOMS 8 HYDROGEN

5 0
3 years ago
How many atoms of Kr (Krypton) are in a balloon that contains 2.00 mol of Kr? (4)
Svetllana [295]

Answer:

atoms= 1.204x10^{24}atoms

Explanation:

Hello!

In this case, according to the Avogadro's number, it is possible to compute the atoms of Kr in 2.00 moles as shown below:

atoms=2.00mol*\frac{6.022x10^{23}atoms}{1mol} \\\\atoms= 1.204x10^{24}atoms

Best regards!

4 0
2 years ago
Classify each of the following as energy primarily transferred as HEAT or energy primarily transferred as WORK.
IgorLugansk [536]
number 1 is work number 2 is heat
6 0
3 years ago
How many molecules of XeF6 are formed from 12.9 L of F2 (at 298 K and 2.6 atm) according to 11) the following reaction? Assume t
ddd [48]

Answer:

#Molecules XeF₆ = 2.75 x 10²³ molecules XeF₆.

Explanation:

Given … Excess Xe + 12.9L F₂ @298K & 2.6Atm => ? molecules XeF₆

1. Convert 12.9L 298K & 2.6Atm to STP conditions so 22.4L/mole can be used to determine moles of F₂ used.

=> V(F₂ @ STP) = 12.6L(273K/298K)(2.6Atm/1.0Atm) = 30.7L F₂ @ STP

2. Calculate moles of F₂ used

=> moles F₂ = 30.7L/22.4L/mole = 1.372 mole F₂ used

3. Calculate moles of XeF₆ produced from reaction ratios …

Xe + 3F₂ => XeF₆ => moles of XeF₆ = ⅓(moles F₂) = ⅓(1.372) moles XeF₆ = 0.4572 mole XeF₆

4. Calculate number molecules XeF₆ by multiplying by Avogadro’s Number  (6.02 x 10²³ molecules/mole)

=> #Molecules XeF₆ = 0.4572mole(6.02 x 10²³ molecules/mole)

                                  = 2.75 x 10²³ molecules XeF₆.

8 0
3 years ago
CHEMISTRY HELP !?????
zheka24 [161]

3. Plasma

- indefinite shape & volume

- affected by magnetic and electric field

- drift and flow freely


4. Liquids have fixed volume meaning packed tighter together as gases do not have fixed shape or volume .

D would be correct

8 0
3 years ago
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