Answer:
d
. H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O
Explanation:
a
. 2HgO → 2Hg + O₂,
It is a decomposition reaction, that HgO is decomposed to give Hg and O.
b
. Na₂SO₄ + BaCl₂ → BaSO₄ + 2NaCl,
It is a double replacement reaction where two salts replaces their cations and anions with each others producing 2 new salts.
c
. Zn + 2AgNO₃ → Zn(NO₃)₂ + 2Ag,
It is a single replacement reaction, that Zn replaces Ag from its salt.
d
. H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O
It is acid-base reaction "neutralization reaction" where H₂SO₄ (acid) reacts with KOH (base) producing K₂SO₄ (salt) and water.
<em>d
. H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O</em>
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Answer is: <span> two samples have in common same amount of substance and same number of particles.
1) There are same amount of substance in both beakers:
n(Zn) = 1 mol.
n(ZnCl</span>₂) = 1 mol.
2) There are same number of particles (atoms, molecules, ions) in both beakers:
N(Zn) = n(Zn) · Na.
N(Zn) = 1 mol · 6.023·10²³ 1/mol = 6.023·10²³ atoms of zinc.
N(ZnCl₂) = n(ZnCl₂) · Na.
N(ZnCl₂) = 1 mol · 6.023·10²³ 1/mol = 6.023·10²³ molecules of zinc(II) chloride.
Na - Avogadro number.
