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aleksley [76]
3 years ago
15

How is the chemical symbol of an element determined

Chemistry
2 answers:
elena55 [62]3 years ago
7 0
There are 4 ways: first letter, first 2 letters, first and third letter, or a derivative of the original element name
viktelen [127]3 years ago
4 0
The chemical symbol of an element is determined by the language used to abbreviate the element. Most chemical symbols use abbreviations of the English name for the element, such as "O" for oxygen, "H" for hydrogen or "Ar" for argon.
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After 1911, most scientists accepted the theory that the nucleus of an atom was very dense and very small and had a positive cha
Scorpion4ik [409]

Answer:

I believe it is D

Explanation:

since Rutherford's explanation, when he made it in 1911, was that scattering was caused by a hard, dense court to centre of the Adam, which is the nucleus and he used Alpha particles to observe the scattered backwards from a gold foil

4 0
3 years ago
If the density of a liquid is 5 g/mL and the mass is 65 g, what would the volume be?
Katyanochek1 [597]

Answer:

Volume would be 13

Explanation:

Divide the mass by the density

65/5

5 0
3 years ago
Read 2 more answers
Find δs∘ for the reaction between nitrogen gas and hydrogen gas to form ammonia:12n2(g) 32h2(g)→nh3(g)
Dima020 [189]

Nitrogen (N2) and hydrogen (H2) gases react to form ammonia, which requires -99.4 J/K of standard entropy (ΔS°).

What is standard entropy?

The difference between the total standard entropies of the reaction mixture and the summation of the standard entropies of the outputs is the standard entropy change. Each entropy in the balanced equation needs to be compounded by its coefficient, as shown by the letter "n."

Calculation:

Balancing the given reaction following-

1/2 N₂(g) + 3/2 H₂ (g)→ NH₃ (g)

ΔS° = [1 mol x S° (NH₃)g] - [1/2 mol x S° (N₂)g] - [3/2 mol x S°(H₂)g]

Here S° = standard entropy of the system

Insert into the aforementioned equation all the typical entropy values found in the literature:

ΔS° = [1 mol x 192.45 J/mol.K] - [1/2 mol x 191.61 J/mol.K] - [3/2 mol x 130.684 J/mol.K]

⇒ΔS° = - 99.4 J/K

Therefore, the standard entropy, ΔS° is -99.4 J/K.

Learn more about standard entropy here:

brainly.com/question/14356933

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5 0
1 year ago
A compound distributes between benzene (solvent 1) and water (solvent 2) with a distribution coefficient, K = 2.7. If 1.0g of th
mote1985 [20]

Explanation:

The given data is as follows.

Solvent 1 = benzene,          Solvent 2 = water

 K_{p} = 2.7,         V_{S_{2}} = 100 mL

V_{S_{1}} = 10 mL,       weight of compound = 1 g

       Extract = 3

Therefore, calculate the fraction remaining as follows.

                  f_{n} = [1 + K_{p}(\frac{V_{S_{2}}}{V_{S_{1}}})]^{-n}

                                  = [1 + 2.7(\frac{100}{10})]^{-3}

                                  = (28)^{-3}

                                  = 4.55 \times 10^{-5}

Hence, weight of compound to be extracted = weight of compound - fraction remaining

                                  = 1 - 4.55 \times 10^{-5}

                                  = 0.00001

or,                               = 1 \times 10^{-5}

Thus, we can conclude that weight of compound that could be extracted is 1 \times 10^{-5}.

7 0
3 years ago
Read 2 more answers
Hello, I study Home MS Physical Science B-IC. Are there quizlets I can look up for the cumulative exam I have to take today?
Ludmilka [50]
Yes if you search up your subject or topic then put quizlet you’ll find your answer but you may need to login in to get the best experience of studying that you want
8 0
3 years ago
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