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kobusy [5.1K]
3 years ago
6

Could be With this tool, the separated from the

Chemistry
1 answer:
hoa [83]3 years ago
8 0

Answer:

Check the picture below my freins

Explanation:

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Facilitated diffusion is a form of passive transport and involves the movement of molecules (like glucose) that are too large to
Helga [31]

Answer: Membrane Protiens

Explanation:

In facilitated diffusion, molecules diffuse across the plasma membrane with assistance from membrane proteins, such as channels and carriers. A concentration gradient exists for these molecules, so they have the potential to diffuse into (or out of) the cell by moving down it.

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3 years ago
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2 AL and 6 HCL AND 2 ALCL3 and 3 H2

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What will be the ph of a buffer solution with an acid (pka6. 1) that is exactly half as concentrated as its conjugate base?
anygoal [31]

The pH of a buffer solution with acid that (PKA 6. 1) is exactly half as concentrated as its conjugate base is 6.4.

<h3>What is a buffer solution?</h3>

A buffer solution is a solution that has a maintained pH, not basic or not acidic. Its pH changes when acid or base is added to the solution.

We had to figure out the acid's concentration, which is exactly half that of its potential base.

We know that pH = pH_log

We have less than 6.1 pH so this is a conjugated base.

This will equal to 6.1 + log2 = 6.4

Thus, the pH of a buffer solution with acid is 6.4.

To learn more about buffer solutions, refer to the below link:

brainly.com/question/13169083

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7 0
2 years ago
A sample of 2.45g aluminum oxide decomposes into 1.3g of aluminum and 1.15g of oxygen. What is the percentage composition of the
Vitek1552 [10]

Answer:

%Al = 53.1%%

%O = 46.9%

Explanation:

If we know the grams of a chemical compound in a specific reaction, it is possible to know the percentage of each atom that composes it.

For the Aluminum Oxide in this problem, we know its total weight and the grams of each component.

therefore we can determine the percentage ratio of its components through:

For Al

%Al = \frac{mass of Al}{mass of Aluminium oxide} . 100%

% Al = \frac{1,3 g}{2,45 g} . 100%

%Al = 53.1%%

In the same way for oxygen

%O = \frac{mass of O}{mass of Aluminium oxide} . 100%

%O = \frac{1,5 g}{2,45 g} . 100%

%O = 46.9%

5 0
3 years ago
How many grams of ethylene (C2H4) are needed to produce 140 grams of carbor<br>dioxide? ​
Leto [7]

Answer:5

Explanation:

just trust me 5

4 0
3 years ago
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