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3 years ago

15

Hello can someone plss help me with this question!!

1 answer:

telo118 [61]3 years ago

6 0

Answer:

The answer for the question is Newton

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Akimi4 [234]

Answer:

Molality, Solvent, Solute, Mole fraction, Molarity.

Explanation:

The expression of concentration that provides the moles of solute per kilograms of solvent is Molality. This in the only expression referred to the solvent.

A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the Solvent is water. When water is present, it is usually considered the solvent.

A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the Solute is sodium chloride. There can be 1 or more solutes in a solution.

If you place 5 moles of sodium chloride and 4 moles of sucrose into 11 moles of water, the Mole fraction of sodium chloride would be 0.25. The mole fraction is equal to the moles of a substance divided by the total number of moles.

A way to express concentration that provides the moles of solute per liter of solution is Molarity.

8 0

4 years ago

Given: 36.7 grams of CaF2 is added to 300 mL water. Find molarity?

BigorU [14]

<h3>Answer:</h3>

2 M

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Unit 0</u>

Reading a Periodic Table
Using Dimensional Analysis

<u>Aqueous Solutions</u>

Molarity = moles of solute / liters of solution

<h3>Explanation:</h3>

<u>Step 1: Define</u>

36.7 g CaF₂

300 mL H₂O

<u>Step 2: Identify Conversions</u>

Molar Mass of Ca - 40.08 g/mol

Molar Mass of F - 19.00 g/mol

Molar Mass of CaF₂ - 40.08 + 2(19.00) = 78.08 g/mol

1000 mL = 1 L

<u>Step 3: Convert</u>

<em>Solute</em>

Set up: $\displaystyle 36.7 \ g \ CaF_2(\frac{1 \ mol \ CaF_2}{78.08 \ g \ CaF_2})$
Multiply: $\displaystyle 0.470031 \ mol \ CaF_2$

<em>Solution</em>

Set up: $\displaystyle 300 \ mL \ H_2O(\frac{1 \ L \ H_2O}{1000 \ mL \ H_2O})$
Multiply: $\displaystyle 0.3 \ L \ H_2O$

<u>Step 4: Find Molarity</u>

Substitute [M]: $\displaystyle x \ M = \frac{0.470031 \ mol \ CaF_2}{.3 \ L \ H_2O}$
Divide: $\displaystyle x = 1.56677 \ M$

<u>Step 5: Check</u>

<em>Follow sig fig rules and round.</em> <em>We are given 1 sig fig as our lowest.</em>

1.56677 M ≈ 2 M

8 0

3 years ago

After three half-lives, what fraction of a radioactive sample remains? 1/8 1/3 1/2 1/6

Scilla [17]

1/8 got it from Yahoo answers and the answer was highlighted with 4 likes.... so most likely thats it

6 0

3 years ago

Read 2 more answers

Aldehydes and ketones undergo acid-catalyzed reaction with alcohols to yield hemiacetals, compounds that have one alcohol-like o

REY [17]

Answer:

See explaination

Explanation:

See attachment for the structure of the acetal that you would obtain by reaction of cyclopentanone with 1-propanol.

4 0

3 years ago

Oh really<br> How do I look evil, right? Egypt made me brown

olasank [31]

Answer:

ummmmmmmmmmmmmmmmmmmmmmmm

8 0

3 years ago

Read 2 more answers