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Brrunno [24]
3 years ago
13

If sulfur dioxide and oxygen can be made into sulfur trioxide, what is the reverse reaction?

Chemistry
2 answers:
FromTheMoon [43]3 years ago
7 0
Sulfur monoxide, I believe.
tamaranim1 [39]3 years ago
7 0

Unit 3 Lesson 7 Quick Check

1) C

2) A

3) A

4) A

5) B

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Help plz I have to get this done before 2:30 The diagram shows different forms of thermal energy transfer.
MArishka [77]

Answer:

Conduction.

Explanation:

4 0
3 years ago
Read 2 more answers
How many moles are in 5.4x1024 molecules of C4H2F7I, heptafluoro-1-iodobutane? Group of answer choices
jasenka [17]

Given :

Number of molecules of C_4H_2F_7I.

To Find :

How many moles are in given number of molecules.

Solution :

We know, in 1 moles of any element/compound contains 6.022\times 10^{23} at atoms/molecules.

So, number of moles in 5.4\times 10^{24} molecules are :

n = \dfrac{5.4\times 10^{24}}{6.022\times 10^{23}}\\\\n = 8.97 \ moles

Therefore, number of moles are 8.97 .

4 0
2 years ago
The region in which an electron is likely to be found is known as a(n) ____________.
Zinaida [17]

Answer:

orbital

Explanation:

electrons are found in an orbital

3 0
3 years ago
Zn +
saul85 [17]

Answer:

1. Theoretical yield = 2.03g

2. Actual yield 1.89g

Explanation:

Let us write a balanced equation. This is illustrated below:

Zn + 2HCI —> ZnCl2 + H2

Molar Mass of HCl = 1 +35.5 = 36.5g/mol

Mass of HCl from the balanced equation = 2 x 36.5 = 73g

Molar Mass of H2 = 2x1 = 2g/mol

1. From the equation,

73g of HCl produced 2g of H2.

Therefore, 74g of HCl will produce = (74 x 2)/73 = 2.03g

Therefore, theoretical yield = 2.03g

2. %yield = 93%

Theoretical yield = 2.03g

Actual yield =?

%yield = Actual yield /Theoretical yield x100

Actual yield = %yield x theoretical yield

Actual yield = 93% x 2.03 = (93/100)x2.03 = 1.89g

Actual yield =1.89g

4 0
4 years ago
In which set do all elements tend to form anions in binary ionic compounds? li, na, k n, o, i c, s, pb k, fe, br?
pav-90 [236]

Atoms or molecule after gaining of electron possesses negative charge and is known as anion.

For the given sets:

  • Li, Na, K

The given elements are alkali metals and have tendency to lose electrons easily and form cations.

  • N, O, I

The given elements are non-metals and are electronegative. So, they gain electrons easily and form anion.

  • C, S, Pb

Carbon has tendency to form bond by sharing of electrons, Sulfur has tendency to gain electrons and form anion whereas Lead has tendency to lose electron.

  • K, Fe, Br

Potassium and Iron has tendency to lose electron and form cation whereas Bromine has tendency to gain electron to form anion.

Hence, from the given sets, all elements of set: N, O, I have tendency to form anions in binary ionic compounds.

8 0
3 years ago
Read 2 more answers
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