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Luden [163]
4 years ago
15

The hydrogen ion concentration of these two solutions differ from each other by a factor of .

Chemistry
1 answer:
ElenaW [278]4 years ago
3 0

Anser:

(B)10

Explanation:

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Answer:<em>The three states of matter are the three distinct physical forms that matter can take in most environments: solid, liquid, and gas. In extreme environments, other states may be present, such as plasma, Bose-Einstein condensates, and neutron stars.</em>

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Explanation:

I'm pretty positive that's the right answer.........

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Please help!!!!! I need the correct answer quickly!!!
xxMikexx [17]

Answer :

The oxidation state of oxygen (O) in OF_2  is, (+2)

The oxidation state of carbon (C) in CO  is, (+2)

The oxidation state of nitrogen (N) in K_3N  is, (-3)

Explanation :

Oxidation number : It represent the number of electrons lost or gained by the atoms of an element in a compound.

Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.

When the atoms are present in their elemental state then the oxidation number will be zero.

Rules for Oxidation Numbers :

The oxidation number of a free element is always zero.

The oxidation number of a monatomic ion equals the charge of the ion.

The oxidation number of  Hydrogen (H)  is +1, but it is -1 in when combined with less electronegative elements.

The oxidation number of  oxygen (O)  in compounds is usually -2, but it is -1 in peroxides.

The oxidation number of a Group 1 element in a compound is +1.

The oxidation number of a Group 2 element in a compound is +2.

The oxidation number of a Group 17 element in a binary compound is -1.

The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.

The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

(a) The given compound is, OF_2

Let the oxidation state of 'O' be, 'x'

x+2(-1)=0\\\\x-2=0\\\\x=+2

The oxidation state of oxygen (O) in OF_2  is, (+2)

(b) The given compound is, CO

Let the oxidation state of 'C' be, 'x'

x+(-2)=0\\\\x-2=0\\\\x=+2

The oxidation state of carbon (C) in CO  is, (+2)

(c) The given compound is, K_3N

Let the oxidation state of 'N' be, 'x'

3(+1)+x=0\\\\3+x=0\\\\x=-3

The oxidation state of nitrogen (N) in K_3N  is, (-3)

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does that answer it?

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