Answer:
#1: 0.00144 mmolHCl/mg Sample
#2: 0.00155 mmolHCl/mg Sample
#3: 0.00153 mmolHCl/mg Sample
Explanation:
A antiacid (weak base) will react with the HCl thus:
Antiacid + HCl → Water + Salt.
In the titration of antiacid, the strong acid (HCl) is added in excess, and you're titrating with NaOH moles of HCl that doesn't react.
Moles that react are the difference between mmoles of HCl - mmoles NaOH added (mmoles are Molarity×mL added). Thus:
Trial 1: 0.391M×14.00mL - 0.0962M×34.26mL = 2.178 mmoles HCl
Trial 2: 0.391M×14.00mL - 0.0962M×33.48mL = 2.253 mmoles HCl
Trial 3: 0.391M×14.00mL - 0.0962M×33.84mL = 2.219 mmoles HCl
The mass of tablet in mg in the 3 experiments is 1515mg, 1452mg and 1443mg.
Thus, mmoles HCl /mg OF SAMPLE<em> </em>for each trial is:
#1: 2.178mmol / 1515mg
#2: 2.253mmol / 1452mg
#3: 2.219mmol / 1443mg
<h3>#1: 0.00144 mmolHCl/mg Sample</h3><h3>#2: 0.00155 mmolHCl/mg Sample</h3><h3>#3: 0.00153 mmolHCl/mg Sample</h3>
Group 7 elements (halogens)
Answer:
The law of conservation of matter states that in a chemical reaction matter cannot be created or destroyed
Explanation:
Answer:
The correct answer is A electron on the aniline nitrogen are somehow delocalized to the aromatic ring.
Explanation:
The structure of aniline contain double bonds and lone pair of electron in the nitrogen atom of -NH2 group that is attached to the benzene ring.
The electron pair present in the nitrogen atom of -NH3 group of aniline undergo delocalization with the aromatic ring of benzene resulting in the formation of resonance hybrid that increases the ability of nitrogen atom of -NH2 group of aniline to easily donate that lone pair of electron.
ON the other hand the resonance stabilization cannot be possible with the cyclohexylamine ring as it is saturated.
The valence electron is the outermost shell
