A chlorine concentrations of 0.500 ppm is desired for water purification. What mass of chlorine must be added to 2500 L of water
1 answer:
You might be interested in
Answer:- cell potential = -0.19 volts
Solution:- The equation that shows the connection between and cell potential, E is written as:
in this equation, n stands for moles of electrons, E stands for cell potential and F stands for faraday constant and it's value is .
It asks to calculate the value of E, so let's rearrange the equation:
Let's plug in the values in it:
since,
Where C stands for coulombs and V stands for volts.
So,
E = -0.19 V
So, the cell potential is -0.19 volts.