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Aleks04 [339]
3 years ago
11

A chlorine concentrations of 0.500 ppm is desired for water purification. What mass of chlorine must be added to 2500 L of water

to achieve this level?
Chemistry
1 answer:
Readme [11.4K]3 years ago
5 0

Answer:

50g

Explanation:

pls mark me brainliest right

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How many moles of no2 are equivalent to 74.3g of no2
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<h3><u>Answer;</u></h3>

= 1.615 moles

<h3><u>Explanation</u>;</h3>

The molar mass of NO2

 = 46.01 g/mol

The mass of NO2 given is 74.3 g

Number moles = mass/ molar mass

                        = 74.3 g/ 46.01 g/mol

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6 0
2 years ago
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How do you solve this ??
ICE Princess25 [194]

Answer:

Option D. 400 mmHg

Explanation:

The following data were obtained from the question:

Mole of He (nHe) = 0.04 mole

Mole of Ne (nNe) = 0.06 mole

Total pressure = 10³ mmHg

Partial pressure of He =.?

Next, we shall determine the total number of mole in the reaction vessel.

This can be obtained as follow:

Mole of He (nHe) = 0.04 mole

Mole of Ne (nNe) = 0.06 mole

Total mole =?

Total mole = nHe + nNe

Total mole = 0.04 + 0.06

Total mole = 0.1

Next, we shall determine the mole fraction of He.

This can be obtained as follow:

Mole fraction = mole of gas /total mole

Mole of He (nHe) = 0.04 mole

Total mole = 0.1

Mole fraction of He =.?

Mole fraction of He = nHe/total mole

Mole fraction of He = 0.04/0.1

Mole fraction of He = 0.4

Finally, we shall determine the partial pressure of He as follow:

Partial pressure = mole fraction x total pressure

Mole fraction of He = 0.4

Total pressure = 10³ mmHg

Partial pressure of He =.?

Partial pressure of He = 0.4 x 10³

Partial pressure of He = 400 mmHg.

Therefore, the partial pressure of He is 400 mmHg.

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