Magnetic field 'B' at a distance 'r' from an substantially
large conductor carrying current 'i' = (2x10^ -7)('i' ) / r
Magnetic field 'B' beyond the wire= (2x10^ -7)(8.15x10^18x1.6x10^ - 19 ) /0.046
=5.7 x10^ -12 tesla
As electrons move from west to east, the conventional current is from east to
west.
By means of Maxwell's right handed corkscrew rule, the way of magnetic field is
from south to north.
Answer:
So increasing the voltage increases the charge in direct proportion to the voltage. If the voltage exceeds the capacitors rated voltage, the capacitor may fail due to breakdown of the dielectric between the two plates that make up the capacitor.
Explanation:
A option.
Answer:


Explanation:
Given:
- minimum amplitude at the start of oscillation cycle,

- the first maximum amplitude after the start of oscillation cycle,

- Time taken to reach from the first minima to the first maxima,

As we know that an oscilloscope executes a wave cycle represented by a sine wave. So we can deduce that it has executed one-fourth of the cycle in going from the amplitude of 20 units to 100 units in 0.005 seconds.
<u>So the time taken to complete one cycle of the oscillation:</u>

is the time period of the oscillation
<u>We know frequency:</u>



Answer:
s = 1.7 m
Explanation:
from the question we are given the following:
Mass of package (m) = 5 kg
mass of the asteriod (M) = 7.6 x 10^{20} kg
radius = 8 x 10^5 m
velocity of package (v) = 170 m/s
spring constant (k) = 2.8 N/m
compression (s) = ?
Assuming that no non conservative force is acting on the system here, the initial and final energies of the system will be the same. Therefore
• Ei = Ef
• Ei = energy in the spring + gravitational potential energy of the system
• Ei = \frac{1}{2}ks^{2} + \frac{GMm}{r}
• Ef = kinetic energy of the object
• Ef = \frac{1}{2}mv^{2}
• \frac{1}{2}ks^{2} + (-\frac{GMm}{r}) = \frac{1}{2}mv^{2}
• s =
s =
s = 1.7 m
Where is the cube I don't see any picture?