Question

ed at the center of mass of the seesaw. The second child has one-half the mass of the first child. Where should the second child sit to balance the seesaw? Two children want to balance horizontally on a seesaw. The first child is sitting one meter to the left of the pivot point located at the center of mass of the seesaw. The second child has one-half the mass of the first child. Where should the second child sit to balance the seesaw? 2m to the right of the pivot 0.5m to the right of the pivot 4m to the right of the pivot 1m to the right of the pivot

Answer 1

Answer:2 m right

Explanation:

Given

First child is sitting  1 m left from Pivot point

Mass of second child is half of first

Let mass of first child be  m

Second child $\frac{m}{2}$

In order to balance see saw torque must be zero about pivot

$m\times 1=\frac{m}{2}\times x$

x=2 m right from pivot point