D. radioactive isotopes are one of the environmental waste products of nuclear energy.
Without solving for the dipole moment, we can easily determine which among the common gases has the smallest dipole moment just by determining the differences in their electronegativity. The greater the difference in the electronegativity, the higher is the value of the dipole moment.
From the given above, there are obvious differences between the electronegativity between the atoms composing LiF, ClF, and HF. For Cl2, since this is the same molecule then, the difference in the electronegativity is zero.
Answer: Cl2.
Answer:
During the initial cell operation, each reaction is thermodynamically favorable, but the larger operating potential of the lithium-iodine cell indicates that its cell reaction is more thermodynamically favorable. ( B )
During the initial cell operation, the oxidation of iodine is thermodynamically favorable but the oxidation of mercury is not. ( C )
Explanation:
<u>The major Differences between The Zinc mercury cell and Lithium-iodine cell are :</u>
During the initial cell operation, each reaction is thermodynamically favorable, but the larger operating potential of the lithium-iodine cell indicates that its cell reaction is more thermodynamically favorable. and
During the initial cell operation, the oxidation of iodine is thermodynamically favorable but the oxidation of mercury is not.
Given the relationship below,
Δ G = -nFE
E = emf of cell , G = free energy.
This relationship shows that if E is positive the reaction will be thermodynamically favorable also if E is large it will increase the negativity of free energy also From the question we can see that with the reduction of mercury the value of E is more positive and this shows that Mercury is thermodynamically unfavorable
Answer:
4H₂O₂ → 4H₂O + 2O₂
Explanation:
The chemical reaction for the decomposition of hydrogen peroxide can be represented as follows;
2H₂O₂ → 2H₂O + O₂
Therefore, two molecules of hydrogen peroxide decomposes into two molecules of water and one molecule of oxygen.
In a related diagram, we have 4 molecules of hydrogen peroxide decomposing, therefore we have;
4H₂O₂ → 4H₂O + 2O₂
The attached diagram shows the products of the decomposition of the four molecules of hydrogen peroxide.
Answer: good luck with that F
Explanation:
