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aleksandr82 [10.1K]
3 years ago
7

Hydrogen peroxide, H2O2, decomposes according to the equation above. This reaction is thermodynamically favorable at room temper

ature.
(a) A particulate representation of the reactants is shown below in the box on the left. In the box below on the right, draw the particulate representation of all the molecules that would be produced from these four reactant molecules.

Chemistry
1 answer:
s2008m [1.1K]3 years ago
4 0

Answer:

4H₂O₂ → 4H₂O + 2O₂

Explanation:

The chemical reaction for the decomposition of hydrogen peroxide can be represented as follows;

2H₂O₂ → 2H₂O + O₂

Therefore, two molecules of hydrogen peroxide decomposes into two molecules of water and one molecule of oxygen.

In a related diagram, we have 4 molecules of hydrogen peroxide decomposing, therefore we have;

4H₂O₂ → 4H₂O + 2O₂

The attached diagram shows the products of the decomposition of the four molecules of hydrogen peroxide.

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Given the standard enthalpy changes for the following two reactions:
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Answer:

ΔH° = -186.2 kJ

Explanation:

Hello,

This case in which the Hess method is applied to compute the required chemical reaction. Thus, we should arrange the given first two reactions as:

(1) it is changed as:

SnCl2(s) --> Sn(s) + Cl2(g)...... ΔH° = 325.1 kJ

That is why the enthalpy of reaction sign is inverted.

(2) remains the same:

Sn(s) + 2Cl2(g) --> SnCl4(l)......ΔH° = -511.3 kJ

Therefore, by adding them, we obtain the requested chemical reaction:

(3) SnCl2(s) + Cl2(g) --> SnCl4(l)

For which the enthalpy change is:

ΔH° = 325.1 kJ - 511.3 kJ

ΔH° = -186.2 kJ

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answer is A

The kinetic theory is used to explain the behaviour of gases.

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Number of moles in 31.99g O2 <br> And 176.8g NaCl
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#O_2

\\ \sf\longmapsto No\:of\;moles=\dfrac{Given\:mass}{Molar\:mass}

\\ \sf\longmapsto No\:of\:moles=\dfrac{31.99}{32}

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