Hydrogen peroxide, H2O2, decomposes according to the equation above. This reaction is thermodynamically favorable at room temper
ature.
(a) A particulate representation of the reactants is shown below in the box on the left. In the box below on the right, draw the particulate representation of all the molecules that would be produced from these four reactant molecules.
(a) A particulate representation of the reactants is shown below in the box on the left. In the box below on the right, draw the particulate representation of all the molecules that would be produced from these four reactant molecules.
1 answer:
Answer:
4H₂O₂ → 4H₂O + 2O₂
Explanation:
The chemical reaction for the decomposition of hydrogen peroxide can be represented as follows;
2H₂O₂ → 2H₂O + O₂
Therefore, two molecules of hydrogen peroxide decomposes into two molecules of water and one molecule of oxygen.
In a related diagram, we have 4 molecules of hydrogen peroxide decomposing, therefore we have;
4H₂O₂ → 4H₂O + 2O₂
The attached diagram shows the products of the decomposition of the four molecules of hydrogen peroxide.
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Explanation:
It is known that molarity is the number of moles present in a liter of solution.
Mathematically, Molarity =
Hence, calculate the molarity of given solution as follows.
Molarity of citric acid =
=
= 0.173 M
As citric acid is a triprotic acid so, upon dissociation it gives three hydrogen ions.
Normality = Molarity × no. of hydrogen or hydroxide ions
= 0.173 × 3
= 0.519 N
Thus, we can conclude that molarity of given solution is 0.173 and its normality is 0.519 N.