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3 years ago

Na2O + H2O => NaOH * Your answer Balancing equations only the coefficient ratios

Chemistry

1 answer:

prisoha [69]3 years ago

6 0

Answer:

1, 1, 2

Explanation:

You need to have the same amount of atoms of everything element on both the products and reactants side

Reactants:

Na=2

O=2

H=2

Products:

Na=2

O=2

H=2

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Which gas will diffuse at a faster rate, CH4 with a molar mass of 16 g or

vivado [14]

Answer:

CH₄ will diffuse at faster rate.

Explanation:

According to Graham's law,

The rate of diffusion is inversely proportional to the square root of molar mas of gas.

It is given in question the molar mass of CH₄ is 16 g. Thus the square rot of 16 is.

√16 = 4

The molar mass of SO₂ is 64 g and the square root is,

√64 = 16

As it is stated that diffusion rate is inversely related to the square root of molar mass thus the diffusion rate of SO₂ is lower while methane diffuse faster.

8 0

3 years ago

Calculate E o , E, and ΔG for the following cell reactions (a) Mg(s) + Sn2+(aq) ⇌ Mg2+(aq) + Sn(s) where [Mg2+] = 0.025 M and [S

Rudik [331]

E⁰(cell) = 2.24V

E(cell) = 2.246V

∆G = -433 KJ/mol

<u>Explanation:</u>

Mg(s) + Sn²⁺(aq) ⇌ Mg²⁺(aq) + Sn(s)

[Mg2+] = 0.025 M

[Sn2+] = 0.040 M

First we need the standard reduction potentials:

. . . . . . . . . . . . . . . . . E°(V)

Mg²⁺ + 2 e⁻ ⇌ Mg(s). . .−2.372

Sn²⁺ + 2 e⁻ ⇌ Sn(s) . . . −0.13

Take the more negative (or less positive in other cases) one, and write it as an oxidation:

Mg(s) ⇌ Mg²⁺ + 2 e⁻. . .+2.372 V

Combine them,

Mg(s) + Sn²⁺ ⇌ Mg²⁺ + Sn(s)

E°(cell) = +2.372 – 0.13 V = 2.24 V

To get the cell potential under the conditions given, use the Nernst Equation:

E(cell) = E°(cell) – [(0.059)/n]•logQ = 2.24 V – 0.0295 V • log [Mg²⁺]/[Sn²⁺]

Note that the solids don't appear in Q, only the concs. of the dissolved ions.

E(cell) = 2.24 V – 0.0295 V X log (0.025)/(0.040)

= 2.24 + 0.006 V ≈ 2.246 V

The concentration ratio in Q (Sn²⁺ and Mg²⁺) is too close to 1 to shift E(cell) significantly from E°(cell) given the precision I have for the Sn reduction potential.

∆G = –nFE(cell) = –2(96.485 kJ/mol•V)(2.246 V) = –433 kJ/mol

E⁰(cell) = 2.24V

E(cell) = 2.246V

∆G = -433 KJ/mol

4 0

4 years ago

What is the def of chemical equation

Lelechka [254]

Chemical equations are equations that show that the chemical formulas of a substance that has been reacted and/or produced.

4 0

4 years ago

For a given mass of reactants, the energy released is greatest for a reaction involving

kari74 [83]

Answer: Option (D) is the correct answer.

Explanation:

In fusion reaction, two small nuclei combine together to result in the formation of a large nuclei.

Whereas in fission reaction, large nuclei dissociates into two or more small nuclei.

Nuclear fusion releases more energy as compared to nuclear fission.

For example, two hydrogen nuceli fuse together and result in the formation of helium atom along with release of energy.

$^{2}_{1}H + ^{2}_{1}H \rightarrow ^{4}_{2}He + Energy$

3 0

3 years ago

Read 2 more answers

Moles of Fe in 3.13×1022 atoms of Fe

pav-90 [236]

Answer: 0.05 moles

Explanation:

To convert from atoms to moles, you will need Avogadro's number.

Avogadro's number: 6.022×10²³atoms/moles

(3.13×10²²atoms)×(moles/6.022×10²³ atoms)=0.05 moles

The atoms would cancel out and we will be left with our moles.

6 0

4 years ago