Numerical because its the number of assistants.
Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
(2x - 5) (5x - 10)
Use FOIL
10x² - 20x - 25x + 50
10x² - 45x + 50
5( 2x² - 9x + 10)
2x -5
x -2
5(2x - 5)(x -2)
make each equal to 0
2x - 5 = 0
x - 2 = 0
2x - 5 = 0 x - 2 = 0
2x - 5 (+5) = 0 x - 2 (+2) = 0 (+2)
2x = 5 x = 2
x = 5/2
x = 5/2 , 2
hope this helps
I think the answer is 42.
Answer: 3.42 miles
Step-by-step explanation:
5.5 cm converts to 3.41754e-5 miles