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sp2606 [1]
3 years ago
7

Which of the following is NOT an inverse operation?

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
4 0
2. Addition and multiplication
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Nbbbbbb bm, bjh,bnm,bjh
marin [14]

Answer:

value of x is 2 and y is 3

Step-by-step explanation:

here's the solution in attachment.

8 0
3 years ago
ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing. Show your work or give an explaination.
Nina [5.8K]

Answer:

B

Step-by-step explanation:

If you shifted this equation 7 units to the right and 3 down, the new formula would be 4(x-7)^2-19, or answer choice B. Hope this helps!

4 0
3 years ago
Filipo is building a rectangular sandbox . The length of the sandbox is 1 foot longer than twice the width of the sandbox .the p
Alla [95]

Answer:

Part A : D.) 2w + 2(2w+ 1) = 29

Part B : Length of the sandbox is 10 feet.

Step-by-step explanation:

Given,

Perimeter = 29 ft

We need to find the equation for the perimeter and also the length of the sandbox.

Solution,

Let the width of the sandbox be 'w'.

Now as per question said;

The length of the sandbox is 1 foot longer than twice the width of the sandbox.

So we can say that;

Length = 2w+1

Now we know that the perimeter is equal to the sum of twice of length and width.

framing in equation form, we get;

Perimeter = 2(2w+1)+2w

we have given the perimeter, so on substituting the value, we get;

29=2(2w+1)+2w

Hence The equation used to find the width is  29=2(2w+1)+2w.

Now we solve for 'w'.

Applying distributive property, we get;

4w+2+2w=29\\\\6w+2=29

Subtracting both side by '2' we get

6w+2-2=29-2\\\\6w=27

Dividing both side by 6 we get;

\frac{6w}{6}=\frac{27}{6}\\\\w=4.5\ ft

Width of the sandbox = 4.5 ft

Length of the sandbox = 2w+1=2\times4.5 +1 = 9+1=10\ ft

Hence Length of the sandbox is 10 feet.

3 0
3 years ago
AWSER PLASE IM STUCK ON THIS
dolphi86 [110]
1) 4 2/5 +1/5 = D)4 3/5
2)5 6/9- 1/3 = 5 1/3 or 16/3
3 0
3 years ago
Read 2 more answers
Yin wants to create figure Y′ that is similar to figure Y. Yin begins by reflecting figure Y across the y-axis.
Sholpan [36]

Answer: B) Dilate by scale factor of 2

====================================================

Explanation:

Your teacher isn't saying this directly, but I'm assuming s/he wants you to find a similar figure that isn't congruent to the original. Informally, your teacher seems to want you to find a figure that is the same shape but not the same size as the original.

If so, then any dilation will shrink or enlarge the image depending on the scale factor. So the new image will not be the same as the old one. In this case, a dilation with scale factor 2 means the new figure is twice as large (each side is twice as long). But the old image is similar to the new image. The angles keep their values and therefore we get the same shape. This is why choice B is the answer. Again this is assuming what I mentioned in the first paragraph.

Choices A, C, and D are all known as rigid transformations and they preserve the same size of the figure. Applying any of those operations will lead to the same figure (just rotated, reflected or shifted somehow). In other words, applying operations A,C, or D will have us get two congruent triangles. If two triangles are congruent, then they are automatically similar, but not vice versa. This is why we can rule out A,C, and D.

3 0
3 years ago
Read 2 more answers
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