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allochka39001 [22]

3 years ago

5

A car has a maximum acceleration of 2.75 m/s2. What is the new maximum acceleration of the little car if it tows another car tha

t has the same mass?

1 answer:

saveliy_v [14]3 years ago

8 0

Answer:

1.375 m/s²

Explanation:

Twice the mass, half the acceleration

m₁a₁ = F = m₂a₂

m₁2.75 = (2m₁)a₂

a₂ = 2.75/2 = 1.375

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A jet travels at 489 meters per second how long does it take to travel 235 m? answer in seconds

Sladkaya [172]

if in 1 second the jet goes 428 meters and you want to know how long it takes to go 237 meters you just divide 237/428

it can be written like this

_1_ = __x__

428 237

cross multiply

428 times x = 1 times 237

428x=237

divide by 428 on both sides

x= 237/428

x=0.5537 seconds

7 0

4 years ago

Which characteristic accounts for the fact that red lights are used in dark rooms and DO NOT expose negatives during developing?

Svetllana [295]

Answer:

low energy

Explanation:

They use low amounts of energy and don't affect the developing process. The chemicals used and the negative film are affected by regular light and it can destroy the pictures and the development. The red light prevents chemical processes that destroy the photos and that's why it is used in dark rooms.

Hope this was helpful

3 0

3 years ago

Read 2 more answers

An object of mass 4 kg is initially at rest on a frictionless ice rink. It suddenly explodes into three pieces (I have no idea w

Rina8888 [55]

We have two events that occurred on different axes, the most convenient is to perform the operations on the two axes, and then look for the resulting force.

Our values are,

$m_1=1kg\\m_2 = 2kg\\v_1' = 1.2m/s\\v_1''= 0.8m/s$

PAR A) For the X axis, we apply momentum conservation, which is given by,

Total momentum before = Total momentum After

We start from rest, so in X the initial speeds are 0,

$m_1v_1+m_2v_2=m_1v_1'+m_2v_2'$

$0+0 = (1*1.2)+(1)v_2'$

$V_2' = -1.2m/s$

Now we apply for the conservation of the moment, it is part of the rest, so,

$m_1v_1+m_2v_2=m_1v_1''+m_2v_2''$

$0+0=2*0.8+1*v_2''$

$v_2'' = -1.6$

To find the total speed, we simply apply pitagoras,

$V = \sqrt{v_2'^2+v_2^2''}$

$V = \sqrt{1.2^2+1.6^2}$

$V = 2m/s$

PART B) The address is given by,

$tan\theta = \frac{V_2''}{V_2'}$

$\theta = tan^{-1} \frac{V_2''}{V_2'}$

$\theta = tan^{-1} \frac{1.6}{1.2}$

$\theta = 53.31\°$ (Below -x axis)

6 0

4 years ago

An ice skater weighs 500 [N]. He is coasting to the right at a constant velocity of 2 [m/s]. Assume

luda_lava [24]

Answer:

The net force on the skater is zero. ( $F_{net} = 0\,N$ )

Explanation:

According to Newton's First Law, an object is at equilibrium when either it is at rest or moves at constant velocity, which means a net force of zero. Based on the given statement, there are no external forces acting on skate and, therefore, the net force on the skater is zero. ( $F_{net} = 0\,N$ )

4 0

4 years ago

The sun continuously radiates energy into space, some of which is intercepted by the earth. The average temperature of the surfa

Xelga [282]

Answer: Because of the reflects back into space equal amount of radiation as it receives.

Explanation: The Earth's temperature doesn't keep rising because as the Earth receives the radiation from the sun, the Earth reflects back an equal amount of that radiation back to space.

This reflective ability of a planet of the sun radiation incident on it is known as the albedo.

4 0

4 years ago