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STatiana [176]
1 year ago
7

Suppose you need to design a parachute system to help a remote camera land safely

Physics
1 answer:
IgorLugansk [536]1 year ago
4 0

The correct answer is hang glider.

A hang-glider cannot take off from low ground since it has no power. It needs to be launched from a high location, such a mountain or a hill. The major force acting on a hang-glider is gravity. The weight of the wing and the pilot together is this. The push that keeps the aerofoil flying through the air is produced by the weight. The hang-aerofoil glider's wing's form prevents it from falling to the ground like a stone. It results in lift. An area of low pressure is created by the aerofoil's acceleration of the air passing over the top of the wing. The air moving beneath the wing is compressed as the wing moves forward and downward. After then, the aerofoil is lifted up into the region of low pressure.

The air will gradually drop if it is still. A hang-glider descends at a speed of roughly 3.6 km/h (slow walking), or about 1 meter per second. A hang-glider needs to locate air coming up at the same rate as the glider is going down in order to maintain height. A hang-glider can fly along a cliff without losing height, for instance, if there is a light breeze coming straight from the sea, the air is being forced vertically upward by the cliff at 3.6 km/h, and the glider is flying over a vertical coastal cliff. The glider will begin to gain altitude in a stronger breeze.

Some hang-glider pilots equip their craft with tiny motors and propellers. They become microlights as a result and can now take off and climb from flat ground like a regular aircraft.

To learn more about hang-glider refer the link:

brainly.com/question/1365947

#SPJ9

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Calculate the de Broglie wavelength of an electron traveling at 2.0 x 10^8 m/s (me = 9.1*10^-31 kg).
timofeeve [1]

Answer:

\lambda=3.64\times 10^{-12}\ m

Explanation:

We have,

Speed of an electron is 2\times 10^8\ m/s

It is required to find the De Broglie wavelength of electron. The formula for the De- Broglie wavelength is given by :

\lambda=\dfrac{h}{mv}

h is Planck's constant

m is mass of an electron

Plugging all the values we get :

\lambda=\dfrac{6.63\times 10^{-34}}{9.1\times 10^{-31}\times 2\times 10^{8}}\\\\\lambda=3.64\times 10^{-12}\ m

So, the De-Broglie wavelength of an electron is 3.64\times 10^{-12}\ m

4 0
4 years ago
In this diagram, which force is represted by L?
Dmitry [639]
Answer is a) the force caused by the wend nag encountering wind and air.
8 0
3 years ago
 A balloon is 3m in diameter and is filled with 5 kg of N2. Find the specific volume of the gas in the balloon. Express it in bo
enyata [817]

Answer:

The the specific volume and weight are 79.16m³/k mol and 49 N.

Explanation:

Given that,

Diameter = 3 m

Mass of N₂ = 5 kg

We need to calculate the volume of balloon

Using formula of volume

V= \dfrac{4}{3}\pi r^3

V= \dfrac{4}{3}\pi \times{\dfrac{d}{2}}^3

V= \dfrac{4}{3}\pi \times(\dfrac{3}{2})^3

V=14.137\ m^3

We need to calculate the specific volume in the balloon

Specific\ volume=\dfrac{Volume}{mass}

Specific\ volume=\dfrac{14.137}{5}

Specific\ volume=2.8274\ m^3/kg

Now, Molar mass of N₂ gas is 0.028 kg/mol

Now, Specific volume of N₂ gas in the balloon is

Specific\ volume =0.028\times2.8274=0.0791672\ m^3/mol

Specific\ volume =79.16m^3/kmol

(b). We need to calculate the weight of the gas in the balloon

Weight of the balloon is dependent on the mass of the gas.

The weight of the gas is given by

W = mg

W = 5\times9.8

W = 49\ N

Hence, The the specific volume and weight are 79.16m³/k mol and 49 N.

7 0
4 years ago
Who would have the most potential energy?
snow_lady [41]

Answer:

I'm pretty sure it's A.

4 0
4 years ago
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Exercice 4 :
marta [7]
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