Answer:
best close estimate distance is 315 miles
Explanation:
given data
speed v1 = 50 miles per hour
speed v2 = 60 miles per hour
time t1 = 4 hr
time t2 = 7 hr
to find out
best estimate for the distance traveled
solution
we know lower end distance
distance = v1 × t1
distance = 50 × 4 = 200 miles
and
upper end distance
distance = v2 × t2
distance = 60 × 7 = 420 miles
so middle value distance is
v = 55 miles per hour and t = 5.5 hours
distance = v × t
distance = 55 × 5.5
distance = 302.5 miles
so best close estimate distance is 315 miles
Time = (distance) / (speed)
= (30 km) / (30 m/s)
= (30,000 m) / (30 m/s)
= (30,000 / 30) sec
= 1,000 seconds
= 16 minutes 40 seconds
Absolute strength measures strength adjusted for your body size, while relative strength measurses maximum strength exerted in a single effort. Hopefully that helps wasn't really sure what you were asking seemed like you had answered your own question.
Answer:
The least uncertainty in the momentum component px is 1 × 10⁻²³ kg.m.s⁻¹.
Explanation:
According to Heisenberg's uncertainty principle, the uncertainty in the position of an electron (σx) and the uncertainty in its linear momentum (σpx) are complementary variables and are related through the following expression.
σx . σpx ≥ h/4π
where,
h is the Planck´s constant
If σx = 5 × 10⁻¹²m,
5 × 10⁻¹²m . σpx ≥ 6.63 × 10⁻³⁴ kg.m².s⁻¹/4π
σpx ≥ 1 × 10⁻²³ kg.m.s⁻¹
