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svetlana [45]
4 years ago
13

How much energy is needed to change 100 g of 0o C ice to 0o C water? The latent heat of fusion for water L=335,000 J/kg. Hint: T

he heat (Q) used to change from one phase to another phase of the matter is Q=mL, where L is the latent heat. Its unit is J/kg.
Physics
1 answer:
pychu [463]4 years ago
3 0

Answer:

33.5 kJ

Explanation:

here there is no difference is made in the temperature. Only thing happens here is the conversion of the ice in to water of 0 degree. The heat energy taken from the outside is spent for this conversion.

we have ice 100g =0.1 kg

Appplying Q=mL

                  Q= 0.1 kg * 335 000 J kg^{-1}

                   Q = 33 500 J

                   Q = 33.5 kJ

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baherus [9]

Answer:

DUNNO

Explanation:

BIT BAD FOR 65% WOULD GET -100%

6 0
3 years ago
Calculate the mass of an object with a density of 102.5 g/mL and volume of 375 mL.
AveGali [126]

Answer:

38,437.5

Explanation:

Density(d)= 102.5g/ml

Volume (v)=375ml

Mass(m) = ?

D =m/v

102.5= m/375

102.5*375=m

38,437.5=m

therefore Mass = 38,437.5g/ml.

6 0
4 years ago
How do you test hydrogen gas
Vanyuwa [196]

Explanation:

A splint is lit and held near the opening of the tube, then the stopper is removed to expose the splint to the gas. If the gas is flammable, the mixture ignites. This test is most commonly used to identify hydrogen, which extinguishes with a distinctive 'squeaky pop' sound.

3 0
3 years ago
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pendulum a is 20 cm long and has a 5 g mass on it. pendulum b is 30 cm long and has 10 g mass on it. which one has a faster peri
zhenek [66]

Answer:

a has a faster period

Explanation:

Period only depends on the length, irrelevant to the mass.

a has a shorter length, so has a small period, or faster.

3 0
2 years ago
A horizontal pipe narrows from a radius of 0.250 m to 0.1000 m. If the speed of the water in the pipe is 1.00 m/s in the larger-
umka21 [38]

Answer:

6.25 m/s

196 kg/s

Explanation:

The areas of the pipe from big to small:

A = \pi R^2 = \pi*0.25^2 = 0.196 m^2

a = \pi r^2 = \pi*0.1^2=0.0314m^2

As the product of speed and cross-section area is constant, the speed in the smaller pipe would be

AV = av

v = \frac{AV}{a} = \frac{0.196 * 1}{0.0314} = 6.25 m/s

The mass flow rate would be:

\dot{m} = \ro AV = 1000 * 0.196 * 1 = 196 kg/s

4 0
3 years ago
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