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VashaNatasha [74]
2 years ago
7

Given: Right triangle ABC with altitude Line segment C D

Mathematics
1 answer:
Ipatiy [6.2K]2 years ago
4 0

Answer:

✔ a/f

✔ cf

✔ c/b

✔ cf + ec

✔ c

Step-by-step explanation:

just did it on edg

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Please help, and explain how to solve the problem.
marishachu [46]

Answer:

7 and 9

Step-by-step explanation:

6 0
3 years ago
Insects known as walking sticks move very slowly. They can move 2 inches every 5 seconds. At this rate, how far could a walking
Arisa [49]
2/5 = x/30......2 in to 5 sec = x in to 30 sec
cross multiply
5x = 60
x = 60/5
x = 12 inches <==
6 0
3 years ago
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RESPONDE LAS PREGUNTAS 8, 9 Y 10 DE ACUERDO CON LA
andrew-mc [135]

Answer:  

ANSWER QUESTIONS 8, 9 AND 10 ACCORDING TO THE

NEXT INFORMATION

Luis painted a mural that

has 760 cm of

perimeter; your measurements are

show in the following

figure.

8. The expression associated with the length of the mural: 2x - 40, is

can interpret as

A. the length is 40 cm less than twice its width

B. the length exceeds the width value by 40 cm

C. the width squared, minus 40 cm, equals the length

D. 40 cm minus twice the width is the value of the length

9. What are the measurements in centimeters of the mural?

A. length: 150, width: 190 B. length: 210, width: 250

B. length: 210, width: 250

C. length: 240, width: 140 D. length: 230, width: 190

D. length: 230, width: 190

10. The area Luis used to paint the mural is

A. 2 [(2x - 40) + x] B. 2x2 - 40x

B. 2x2 - 40x

C. (2x) x - 40 D. x2 - 40x

D. x2 - 40x

Step-by-step explanation:

6 0
3 years ago
Suzanne needs material for her school project. She buys 5.50 yards of material at $3.87 a yard. What is the total cost of the ma
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   5.50
x 3.87
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21.285
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Write a definite integral that represents the area of the region. (Do not evaluate the integral.)
joja [24]

Answer:

\int_{-1}^{1}7(x^{3}-x)\:dx

Step-by-step explanation:

1)  The other curve is y=0 then the common points of both curves are x-intercepts, the roots of y=7(x^{3}-x)

y=7(x^{3}-x)\Rightarrow 7(x^3-x)=0 \Rightarrow 7(x^{3}-x)=7x(x-1)(x-1)\Rightarrow \\S=\left ( 0,0 \right ),\left ( -1,0 \right ),\left ( 1,0 \right )

2). Then those intersection points are the upper and the lower limits. Plugging in to this formula for they belong to the interval [-1,1]:

\int_{a}^{b}|f(x)-g(x)dx

\int_{a}^{b}|f(x)-g(x)dx \Rightarrow \int_{-1}^{1}|7(x^{3}-x)-0|dx \Rightarrow \int_{-1}^{1}7(x^{3}-x)\:dx

 

8 0
3 years ago
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