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VashaNatasha [74]
2 years ago
7

Given: Right triangle ABC with altitude Line segment C D

Mathematics
1 answer:
Ipatiy [6.2K]2 years ago
4 0

Answer:

✔ a/f

✔ cf

✔ c/b

✔ cf + ec

✔ c

Step-by-step explanation:

just did it on edg

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A driving school wants to find out which of its two instructors is more effective at preparing students to pass the state’s driv
jonny [76]

Answer:

Yes, there is evidence to support that claim that instructor 1 is more effective than instructor 2

Step-by-step explanation:

We can conduct a hypothesis test for the difference of 2 proportions.  If there is no difference in instructor quality, then the difference in proportions will be zero.  That makes the null hypothesis

H0:  p1 - p2 = 0

The question is asking whether instructor 1 is more effective, so if he is, his proportion will be larger than instructor 2, so the difference would result in a positive number.  This makes the alternate hypothesis

Ha:  p1 - p2 > 0

This is a right tailed test (the > or < sign always point to the critical region like an arrowhead)

We will use a significance level of 95% to conduct our test.  This makes the critical values for our test statistic: z > 1.645.  

If our test statistic falls in this region, we will reject the null hypothesis.

<u>See the attached photo for the hypothesis test and conclusion</u>

7 0
3 years ago
UGH these math problems tho please help!
Dovator [93]

Answer:

#6 would be 15/7

#7 would be 4/90

#8 would be 17/12

i can't see number 9

#11 would be 65/15 or 4.3333333


31 + 34

Step-by-step explanation:


7 0
3 years ago
Read 2 more answers
Write the equation of the linear relationship in slope-intercept form, using decimals as needed.
d1i1m1o1n [39]
Ok so look for the change between x and y.
7 0
3 years ago
Read 2 more answers
Need to know the population in 2015
Margarita [4]
\bf P=1110.9e^{kt}\quad &#10;\begin{cases}&#10;P=1200 &\textit{in thousands}\\&#10;t=2 &\textit{in 2002}&#10;\end{cases}\implies 1200=1110.9e^{k2}&#10;\\\\\\&#10;\cfrac{1200}{1110.9}=e^{2k}\implies ln\left( \frac{1200}{1110.9} \right)=ln(e^{2k})\implies ln\left( \frac{1200}{1110.9} \right)=2k&#10;\\\\\\&#10;\cfrac{ln\left( \frac{1200}{1110.9} \right)}{2}=k\implies 0.0385755\approx k\implies 0.0386\approx k\\\\&#10;-------------------------------\\\\

\bf P=1110.9e^{0.0386t}\qquad &#10;\begin{cases}&#10;t=14\\&#10;\textit{year 2015}&#10;\end{cases}\implies P=1110.9e^{0.0386\cdot 14}&#10;\\\\\\&#10;P\approx 1907.0747\implies about\ 1,907,075\textit{ once rounded up}
3 0
3 years ago
Solve equation:<br><img src="https://tex.z-dn.net/?f=y%20%2B%20%20%5Cfrac%7B7%7D%7B8%7D%20%20%3D%20%20%5Cfrac%7B3%7D%7B8%7D%20"
Gala2k [10]

Answer: y = -1/2

Step-by-step explanation:

Subtract both sides by 7/8

y = 3/8 - 7/8

Then combine like terms

y = -4/8

Then simplify

y = -1/2

4 0
3 years ago
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