All categories

3 years ago

List the vertex Name the roots of the graph

Mathematics

1 answer:

Pavlova-9 [17]3 years ago

7 0

This is my answer for this question (- 201) x= -1. X=4

You might be interested in

Could anyone explain to me what Y is? and if so how u got there?

expeople1 [14]

Y is the variable in the equation.

4 0

3 years ago

Multiply 640 times 3 using partial products

Leno4ka [110]

213r1 or 213.3repeating

5 0

3 years ago

Read 2 more answers

a group of students help a fundraiser last year and raised $950 for charity . This year, they raised $1,045. What is the percent

MakcuM [25]

1045-950 = 95

95/950 = 0.1 = 10% increase

4 0

3 years ago

Read 2 more answers

John runs to the market and comes back in 15 minutes. His speed on the way to the market is 5m/s and his speed on the way back i

katen-ka-za [31]

Answer:

The distance to the market is 2000 m

Step-by-step explanation:

∵ John runs to the market and comes back in 15 minutes

→ Change the min. to the sec. because the unit of his speed is m/s

∵ 1 minute = 60 seconds

∴ 15 minutes = 15 × 60 = 900 seconds

→ Assume that t1 is his time to the market and t2 is his time from

the market

∵ t1 + t2 = 15 minutes

∴ t1 + t2 = 900 ⇒ (1)

→ Assume that the distance to the market is d

∵ His speed on the way to the market is 5m/s

∵ Time = Distance ÷ Speed

∴ t1 = d ÷ 5 ⇒ (1 ÷ 5 = 0.2)

∴ t1 = 0.2d ⇒ (2)

∵ His speed on the way back is 4m/s

∴ t2 = d ÷ 4 ⇒ (1 ÷ 4 = 0.25)

∴ t2 = 0.25d ⇒ (3)

→ Substitute (2) and (3) in (1)

∵ 0.2d + 0.25d = 900

∴ 0.45d = 900

→ Divide both sides by 0.45

∴ d = 2000 m

∴ The distance to the market = 2000 m

8 0

3 years ago

Humood's house is (-5,7)

grin007 [14]

The distance from Humood's house to the school is 500m

<h3>How to determine the distance from Humood's house to the school?</h3>

The given parameters are:

Humood's house is (-5,7)

The school is (3,1)

The distance between both points is calculated using

$d = \sqrt{(x_2- x_1)^2 + (y_2 - y_1)^2$

Substitute the known values in the above equation

$d = \sqrt{(-5 - 3)^2 + (7 - 1)^2$

Evaluate

d = 10

Each unit in the graph is 50m.

So, we have

Distance =10 * 50m

Evaluate the product

Distance = 500m

Hence, the distance from Humood's house to the school is 500m