All estimating problems make the assumption you are familar with your math facts, addition and multiplication. Since students normally memorize multiplication facts for single-digit numbers, any problem that can be simplified to single-digit numbers is easily worked.
2. You are asked to estimate 47.99 times 0.6. The problem statement suggests you do this by multiplying 50 times 0.6. That product is the same as 5 × 6, which is a math fact you have memorized. You know this because
.. 50 × 0.6 = (5 × 10) × (6 × 1/10)
.. = (5 × 6) × (10 ×1/10) . . . . . . . . . . . by the associative property of multiplication
.. = 30 × 1
.. = 30
3. You have not provided any clue as to the procedure reviewed in the lesson. Using a calculator,
.. 47.99 × 0.6 = 28.79 . . . . . . rounded to cents
4. You have to decide if knowing the price is near $30 is sufficient information, or whether you need to know it is precisely $28.79. In my opinion, knowing it is near $30 is good enough, unless I'm having to count pennies for any of several possible reasons.
The domain and the range of the function are all possible values of the x and y, respectively, that function can take.
The range is given by:
The domain is given by:
First of all, you can move the +2x to the other side:
-11 = -26 - 2x
Then you can move the -26 to the other side and then simplify:
-11+26 = -2x
15 = -2x
Then you can divide both sides by 2:
7.5 = -x
Then you can flip the sides and the signs around:
x = -7.5
No, The answer is not -7, it is -7.5
Hope this helps! :)
612.00 in scientific notation is 6.12×10^2
D would be true because if you think about it in percentage wise
2/8= 25%
2/3=66.66%
2/3 is automatically greater than 2/8
Hope this helps :)
