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Ipatiy [6.2K]
3 years ago
6

What is the slope of the line

Mathematics
2 answers:
uysha [10]3 years ago
8 0
B.

Remember Rise over Run, Rise/Run

In this case it rises -3 and runs 5 :)
kolbaska11 [484]3 years ago
6 0

Answer:

B.

Step-by-step explanation: Because when you count them down to 3/5 It's more in the negative.

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Answer:

20=91.35*2

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8 0
2 years ago
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The position of an object along a vertical line is given by s(t) = −t3 + 3t2 + 7t + 4, where s is measured in feet and t is meas
saw5 [17]

Answer:

The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

Step-by-step explanation:

Given : The position of an object along a vertical line is given by s(t) = -t^3+3t^2+7t +4, where s is measured in feet and t is measured in seconds.

To find : What is the maximum velocity of the object in the time interval [0, 4]?

Solution :

The velocity is rate of change of distance w.r.t time.

Distance in terms of t is given by,

s(t) = -t^3+3t^2+7t +4

Derivate w.r.t. time,

v(t)=s'(t) = -3t^2+6t+7

It is a quadratic function so its maximum is at vertex of the function.

The x point of the function is given by,

x=-\frac{b}{2a}

Where, a=-3, b=6 and c=7

t=-\frac{6}{2(-3)}

t=-\frac{6}{-6}

t=1

As 1 lie between interval [0,4]

Substitute t=1 in the function,

v(t)= -3(1)^2+6(1)+7

v(t)= -3+6+7

v(1)=10

Th maximum velocity is 10 ft/s.

Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

8 0
2 years ago
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How do you turn a fraction to a decimal
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3 years ago
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There is no power of 4 that is to 0
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If h(x) = 2x and g(x) = 3x2 + 1, what is h(g(x))?
Lady_Fox [76]

Answer:

h(g(x))=h(3x^2+1)=2(3x^2+1)=6x^2+2

8 0
2 years ago
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