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alekssr [168]
3 years ago
15

Which of the following techniques can be used to separate a heterogeneous mixture into its component parts? (3 points)

Chemistry
2 answers:
avanturin [10]3 years ago
6 0

Answer:

Separation by density

Hope this helps

Nady [450]3 years ago
4 0

Sort by color . I KNOW FOR A FACT ITS THIS THE OTHER ONE IS WRONG.

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____ can be found in many forms including in the chemicals found in food
Rzqust [24]
A. Chemical energy can be in many forms including in the chemicals found in food
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Answer number 3 plzz
SCORPION-xisa [38]

Answer:

energy

Explanation:

it is required energy to remove an electron from an atom

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3 years ago
What metalloid has commonly been used as an insecticide due<br> to its effectiveness as a poison.
Taya2010 [7]

Answer:

Arsenic.

Explanation:

Hello there!

In this case, since insecticides are substances that act as poisons to get rid of insects in order to prevent their presence and/or reproduction in houses, companies, crops and others, a substance that has been widely used is the metalloid arsenic due to its direct affection of the insect's body (movement, performance, cellular functions).

In addition, high levels of arsenic in food could cause arsenic poisoning in humans as well, that is why such practice must be properly performed and by using the correct security protocol.

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3 years ago
Which protists lack cilia and flagella, but can still move around?
timama [110]

Answer: amoebae !

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3 0
3 years ago
ubstance A undergoes a first order reaction A®B with a half-life, t½, of 20 min at 25 °C. If the initial concentration of A in a
Stells [14]

Answer : The concentration of A after 80 min is, 0.100 M

Explanation :

Half-life = 20 min

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{20\text{ min}}

k=3.465\times 10^{-2}\text{ min}^{-1}

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 3.465\times 10^{-2}\text{ min}^{-1}

t = time passed by the sample  = 80 min

a = initial amount of the reactant  = 1.6 M

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

80=\frac{2.303}{3.465\times 10^{-2}}\log\frac{1.6}{a-x}

a-x=0.100M

Therefore, the concentration of A after 80 min is, 0.100 M

3 0
3 years ago
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