3 years ago

Which of the following techniques can be used to separate a heterogeneous mixture into its component parts? (3 points)

Chemistry

2 answers:

avanturin [10]3 years ago

6 0

Answer:

Separation by density

Hope this helps

Nady [450]3 years ago

4 0

Sort by color . I KNOW FOR A FACT ITS THIS THE OTHER ONE IS WRONG.

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Si desea preparar 300 gramos de una solución de azúcar en agua que tenga una concentración de 20% m/m en cuanto gramos de soluto

Digiron [165]

Answer:

$m_{soluto}=60g$

Explanation:

¡Hola!

En este caso, al considerar la unidad de concentración de porcentaje masa/masa, podemos escribir su fórmula como:

$\%m/m=\frac{m_{soluto}}{m_{solucion}}*100\%$

Podemos identificar la masa de soluto (azúcar) como la incógnita, y resolverla como se muestra a continuación:

$m_{soluto}=\frac{\%m/m*m_{solucion}}{100\%}\\\\m_{soluto}=\frac{20\%*300g}{100\%}\\\\m_{soluto}=60g$

¡Saludos!

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3 years ago

What mass of Cu(s) is electroplated by running 24.5A of current through a Cu2+(aq)solution for 4.00 h?Express your answer to thr

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Answer: 116 g of copper

Explanation:

$Q=I\times t$

where Q= quantity of electricity in coloumbs

I = current in amperes = 24.5A

t= time in seconds = 4.00 hr = $4.00\times 3600s=14400s$ (1hr=3600s)

$Q=24.5A\times 14400s=352800C$

$Cu^{2+}+2e^-\rightarrow Cu$

$2\times 96500C=193000C$ of electricity deposits 63.5 g of copper.

352800 C of electricity deposits = $\frac{63.5}{193000}\times 352800=116g$ of copper.

Thus 116 g of Cu(s) is electroplated by running 24.5A of current

Thus remaining in solution = (0.1-0.003)=0.097moles

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