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3 years ago

Explain any three ways of protecting our water bodies

Chemistry

1 answer:

Karo-lina-s [1.5K]3 years ago

7 0

Answer:

Easy Things You Can Do To Protect Drinking Water Sources

Properly dispose of hazardous productsPut up signs. ...

Use and dispose of harmful materials properly. ...

Volunteer in your community. ...

Join in a beach, stream or wetland cleanup. ...

Prepare a presentation about your watershed for a school or civic organization. ...

Organize a storm drain stenciling project.

Explanation:

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Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a flas

valentina_108 [34]

Answer:

Kp = 0.022

Explanation:

Full question: ...With 2.3 atm of ammonia gas at 32. °C. He then raises the temperature, and when the mixture has come to equilibrium measures the partial pressure of hydrogen gas to be 0.69 atm.

The equilibrium of ammonia occurs as follows:

2NH₃(g) ⇄ N₂(g) + 3H₂(g)

Where Kp is defined as:

$Kp = \frac{P_{N_2}P_{H_2}^3}{P_{NH_3}^2}$

Where P represents partial pressure of each gas.

As initial pressure of ammonia is 2.3atm, its equilibrium concentration will be:

P(NH₃) = 2.3atm - 2X

Where X represents reaction coordinate

Thus, pressure of hydrogen and nitrogen is:

P(N₂) = X

P(H₂) = 3X.

As partial pressure of hydrogen is 0.69atm:

3X = 0.69

X = 0.23atm:

P(NH₃) = 2.3atm - 2(0.23atm) = 1.84atm

P(N₂) = 0.23atm

P(H₂) = 0.69atm

$Kp = \frac{0.23atm*0.69atm^3}{1.84atm^2}$

8 0

3 years ago

Oxalic Acid, a compound found in plants and vegetables such as rhubarb, has a mass percent composition of 26.7% C, 2.24% H, and

blondinia [14]

Answer:

HCO₂

Explanation:

From the information given:

The mass of the elements are:

Carbon C = 26.7 g; Hydrogen H = 2.24 g Oxygen O = 71.1 g

To determine the empirical formula;

First thing is to find the numbers of moles of each atom.

For Carbon:

$=26.7 \ g\times \dfrac{1 \ mol }{12.01 \ g} \\ \\ =2.22 \ mol \ of \ Carbon$

For Hydrogen:

$=2.24 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =2.22 \ mol \ of \ Hydrogen$

For Oxygen:

$=71.1 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =4.44 \ mol \ of \ oxygen$

Now; we use the smallest no of moles to divide the respective moles from above.

For carbon:

$\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ carbon$

For Hydrogen:

$\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ hydrogen$

For Oxygen:

$\dfrac{4.44 \ mol \ of \ Oxygen}{2.22} =2 \ mol \ of \ oxygen$

Thus, the empirical formula is HCO₂

4 0

3 years ago

If an atom has six electrons how many protons does it have

Sergio039 [100]

6 protons it have to be neutral

7 0

2 years ago

Calculate the average obtained from the following weighings of the same object. Do not forget to include formulas, units, and th

bazaltina [42]

Answer:

10.4376 g

Explanation:

First we calculate the sum of the weighings:

10.4375 g + 10.4381 g + 10.4373 g + 10.4376 g = 41.7505 g

Then we divide the sum by the number of weighings to calculate the average:

Number of weighings = 4

Average = Sum of weighings / Number of weighings

41.7505 g / 4 = 10.4376 g

6 0

2 years ago

Which type of wave interaction is shown in the photo? with ISSN AN O A. Diffraction O B. Reflection O C. Refraction O D. Absorpt

il63 [147K]

Answer:

I believe the answer is B.) Reflection

I hope I helped! ^-^

6 0

2 years ago