F(x) = 2^x; h(x) = x^3 + x + 8
Table
x f(x) = 2^x h(x) = x^3 + x + 8
0 2^0 = 1 0 + 0 + 8 = 8
1 2^1 = 2 1^3 + 1 + 8 = 10
2 2^2 = 4 2^3 + 2 + 8 = 8 + 2 + 8 = 18
3 2^3 = 8 3^3 + 3 + 8 = 27 + 3 + 8 = 38
4 2^2 = 16 4^3 + 4 + 8 = 76
10 2^10 = 1024 10^3 +10 + 8 = 1018
9 2^9 = 512 9^3 + 9 + 8 = 729 + 9 + 8 = 746
Answer: an approximate value of 10
Answer/explanation :
Step-by-step
subtract 15-8 you have 7 then take
10- ur answer is 7
10-7= 3
Faucet one fills up
of the bathtub in one minute and faucet two fills up
of the bathtub in one minute. If both are one then they will fill up
So, 1/6 of the bathtub in one minute.
Just subtract horizontal 9-5 is 4 and keep the denominator the same
So 5/14 is the answer
