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pantera1 [17]
2 years ago
13

Write the point-slope form of an equation for a line that passes through the point with the given slope

Mathematics
1 answer:
V125BC [204]2 years ago
7 0
<h2>Answer:</h2>

Step 1: Determine the formula.

y - y₁ = m(x - x₁)

Step 2: Determine what variables you need.

(x₁,y₁) = a point on the line

m = slope

Step 3: Plug each number in for the variables and you have the completed point-slope form of the equation for the line.

y - 2 = 2(x - (-2))\\\\y - 2 = 2(x + 2)

The point-slope form of this line is: y - 2 = 2(x + 2).

See the image for the formula I used.

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4. Determine all unknown sides and angles to 1 decimal place.
Ksju [112]

Answer:

The unknown sides are 60.81cm and 51.57cm while the unknown angle is 58degrees

Step-by-step explanation:

4a) Given the following

Opposite side = 38cm (side facing the given angle)

Required

Adjacent and hypotenuse side

According to SOH CAH TOA

tan \theta = \frac{opp}{hyp}\\tan 32=\frac{38}{hyp}\\hyp=\frac{38}{tan 32}\\hyp=\frac{38}{0.6249}\\hyp=  60.81cm

Next is to get the adjacent

Cos 32=\frac{adj}{60.81}\\adj=60.81cos32\\adj=60.81(0.8480)\\adj= 51.57cm

Next is to get the missing

Since sum of angle in the triangle is 180degrees

32 + 90 + x = 180

122 + x = 180

x = 180 - 122

x = 58degrees

7 0
3 years ago
I will mark as brainest
daser333 [38]

subtract 3 from 23 and u will get 20 then divide 2 by 2 and 2 by 20

x= 10

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Simplify the expression<br> (7x + 5) - (2x - 4)
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Answer: 17x+20

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