Which unit would be most appropriate to measure the

irga5000 [103]

Answer:

I can't see what it says u should retake a pic

5 0

3 years ago

A die is rolled 25 times and 12 evens are observed. Calculate and interpret a 95% confidence interval to estimate the true propo

Archy [21]

Answer:

The 95% confidence interval to estimate the true proportion of evens rolled on a die is (0.2842, 0.6758). This means that we are 95% sure that for the entire population of dies, the true proportion of evens rolled on a die is between 0.2842 and 0.6758

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 25, \pi = \frac{12}{25} = 0.48$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.48 - 1.96\sqrt{\frac{0.48*0.52}{25}} = 0.2842$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.48 + 1.96\sqrt{\frac{0.48*0.52}{25}} = 0.6758$

The 95% confidence interval to estimate the true proportion of evens rolled on a die is (0.2842, 0.6758). This means that we are 95% sure that for the entire population of dies, the true proportion of evens rolled on a die is between 0.2842 and 0.6758

8 0

2 years ago

I really dont get this

VikaD [51]

D regular polygon means everything is the same, so the square would be the correct answer.

7 0

3 years ago

Read 2 more answers

Given the function Y=2x-3 complete the table

Irina18 [472]

y=mx+b plus in slope and you get your answer

6 0

2 years ago

A research company desires to know the mean consumption of meat per week among people over age 23. A sample of 164 people over a

Elan Coil [88]

Answer:

The 80% confidence interval for the mean consumption of meat among people over age 23 is between 4 and 4.2 pounds.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.8}{2} = 0.1$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.1 = 0.9$ , so $z = 1.28$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.28*\frac{0.7}{\sqrt{164}} = 0.07$

The lower end of the interval is the mean subtracted by M. So it is 4.1 - 0.07 = 4.03 pounds

The upper end of the interval is the mean added to M. So it is 4.1 + 0.07 = 4.17 pounds

Rounded to one decimal place

The 80% confidence interval for the mean consumption of meat among people over age 23 is between 4 and 4.2 pounds.

8 0

2 years ago