<h2>
Answer with explanation:</h2>
Given : In a restaurant, the proportion of people who order coffee with their dinner is p.
Sample size : n= 144
x= 120

The null and the alternative hypotheses if you want to test if p is greater than or equal to 0.85 will be :-
Null hypothesis :
[ it takes equality (=, ≤, ≥) ]
Alternative hypothesis :
[its exactly opposite of null hypothesis]
∵Alternative hypothesis is left tailed, so the test is a left tailed test.
Test statistic : 

Using z-vale table ,
Critical value for 0.05 significance ( left-tailed test)=-1.645
Since the calculated value of test statistic is greater than the critical value , so we failed to reject the null hypothesis.
Conclusion : We have enough evidence to support the claim that p is greater than or equal to 0.85.
Answer:
7
Step-by-step explanation:
σ = 4 ; μ =?
8.52 to the left of X
.
P(X < 8.52) = 64.8%
P(X < 8.52) = 0.648
Using the Z relation :
(x - μ) / σ
P(Z < (8.52 - μ) / 4)) = 0.648
The Z value of 0.648 of the lower tail is equal to 0.38 (Z probability calculator)
Z = 8.52 - μ / 4
0.38 = 8.52 - μ / 4
0.38 * 4 = 8.52 - μ
1.52 = 8.52 - μ
μ = 8.52 - 1.52
μ = 7
X = quarters
y = dimes
0.25x + 0.10y = 6.95 or 25x + 10y = 695
x + y = 44
25x + 10y = 695
25 (x + y = 44)
25x + 10y = 695
25x + 25y = 1,100
-15y = -405
y = 27 dimes
and 17 quarters
Answer:
58
Step-by-step explanation:
-14 + x = 44
x = 44 + 14
x = 58