<h3>
Answer:</h3>
The percentage recovery is 93.95%
<h3>
Explanation:</h3>
Zinc Chloride (ZnCl₂) decomposes to yield Zinc metal and chlorine gas.
The equation for the reaction is:
ZnCl₂ → Zn(s) + Cl₂(g)
From the reaction:
1 mole of ZnCl₂ decomposes to yield 1 mole of Zn
We are required to calculate the percentage recovery of Zn:
First we calculate the Number of moles of ZnCl₂
Number of moles = Mass ÷ Molar mass
= 3.264 g ÷ 136.286 g/mol
= 0.0239 Moles
Second, we calculate the mole of Zn that would have been obtained if the sample was pure..
From the equation:
But, from the equation 1 mole of ZnCl₂ decomposes to yield 1 mole of Zn
Therefore, the mole ratio is 1 : 1
Hence, moles of Zn = 0.0239 moles
Thirdly, the mass of Zinc that would have been obtained if the sample was pure
Moles of Zn = 0.0239 moles
But; Mass = Moles × Molar mass
Molar mass of Zn = 65.38 g/mol
Therefore;
Mass of Zn = 0.0239 moles × 65.38 g/mol
= 1.5626 g
Fourth, we calculate the percentage recovery
Percentage recovery is given by dividing the amount of sample collected by the amount of sample that was supposed to be collected and expressing it as a percentage.
Therefore;
Amount of Zn obtained = 1.468 g
Amount of Zn that was supposed to be obtained = 1.5626 g
% recovery = (1.468 g÷ 1.5626 g)100%
=93.95%
Therefore, the percentage recovery is 93.95%
