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3 years ago

What transformation is described by the

Mathematics

1 answer:

spayn [35]3 years ago

8 0

Answer:

Step-by-step explanation:

Any alteration to the x value means that the function will move right. There are no exceptions to this that I can think of.

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Describe two ways to solve the equation 2(4x-11)=10

shtirl [24]

2(4x-11) = 10

On dividing 2 on both sides

$\frac{2(4x-11)}{2} = \frac{10}{2}$

$4x-11 = 5$

On Adding 11 on both sides:

$4x-11+11 = 11+5$

$4x = 16$

On dividing both side by 4

$\frac{4x}{4} = \frac{16}{4}$

$x = 4$

Second way is:

We can use distributive property as

$2(4x-11) = 10$

$2*4x- 2*11 = 10$

$8x - 22 = 10$

On Adding 22 on both side

$8x - 22+22 = 10+22$

$8x = 32$

On dividing both side by 8

$\frac{8x}{8} = \frac{32}{8}$

$x = 4$

6 0

3 years ago

A rock drops from a height of 60m. how long does it take for it to hit the ground?

laila [671]

To solve for the time an object takes to hit the ground, the equation

y = y₀ + v₀t + ½gt², or just 0 = y₀ +½gt² since there is no initial velocity and the final y position is 0 (since it is on the ground). Therefore, t = (−2y₀/g)^½.

(-2*60/-9.8)^½ = 3.50 seconds.

8 0

3 years ago

1. Calculate the acceleration of riding her bicycle in a straight line that speeds up from 4 m/s to 12 m/s in 10 seconds. SOLUTI

valentina_108 [34]

<h3>✒️ACCELERATION</h3>

=================================

$\large\sf\underline{Problem:}$

Calculate the acceleration of riding her bicycle in a straight line that speeds up from 4 m/s to 12 m/s in 10 seconds.

=================================

$\large\sf\underline{Answer:}$

$\qquad \qquad \huge \rm = 0.8 \: m/s²$

=================================

$\large\sf\underline{Solution:}$

Here we have a given of,

$\tt{(12\:m/s) \:= \:V_f = (final\: velocity) }$
$\tt{(4\:m/s)\:=\:V_i = (initial \: velocity) }$
$\tt{(10\:sec) \:=\:T = (elapsed time) }$

$\bold{Formula\:||\: Acceleration = \frac{v\: - \:v_0}{t} = \frac{ΔV}{ΔT} }$

Because acceleration has a direction (riding her bicycle in a straight line), it is important to always subtract the final velocity represented as $\bold{V_f}$ from your initial velocity also represented as $\bold{V_i}$ .