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Using the graph provided with the question, we are able to find that that for a concentration of 270 micromol per kilogram, the calcification rate is 20 mmol calcium carbonate per meter squared per day.
Using this calcification rate,
30 = 20 * 1 * days
days = 1.5
The deposition will require 1.5 days.
Replication from formation and separation of the strands
When one phosphate group is removed by breaking a phosphoanhydride bond in a process called hydrolysis, energy is released, and ATP is converted to adenosine diphosphate (ADP). Likewise, energy is also released when a phosphate is removed from ADP to form adenosine monophosphate (AMP)
The surviving species evolve more rapidly
