CAN SOMEONE PLS HELP ME WITH THIS MATH
1 answer:
You might be interested in
Answer:
60 feet
Step-by-step explanation:
The height, h (in meters), of the object launched from a platform is represented by the equation
where x is the time (in seconds) passed after the launch.
The time of launch is (0 seconds passed after the launch)
Substitute to find the height:
Answer:
The first six terms of this arithmetic sequence are: 30, 32, 34, 36, 38, 40
Step-by-step explanation:
The nth term of an arithmetic sequence is given by:
In which d is the common difference, that is, each term is increased by d.
d = 2, Po= 30
First term is 30, each consecutive is increased by 2. So
30, 32, 34, 36, 38, 40
Answer:
Area of the given triangle = 6.51 ft²
Step-by-step explanation:
If we redraw the triangle as shown in the figure attached we get the height of the triangle as x feet and base = 4.3 feet
Therefore area of ΔABC = (1/2) × Height (AD) × Base(BC)
From ΔABD
sin 53 = AD/AB = x/3.8
x = 3.8 × sin 53
= 3.8 × 0.7986 = 3.03 feet
Now area of ΔABC = (1/2)×3.03×4.3 = 6.51 feet²
