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liq [111]
3 years ago
12

HCl(aq)+Ca(OH)2(aq)---------->H2O(I)+?

Chemistry
1 answer:
stiv31 [10]3 years ago
7 0

Answer:

2HCl(aq)+Ca(OH)2(aq)---------->2H2O(I)+ CaCl2(aq)

Strong acids;

H2SO4, HF, HClO4, HI, HBr, HNO3, HCl

Weak acids;

CH3COOH, HNO2, HCN, HCOOH

Strong bases;

LiOH, NaOH, Ca(OH)2, CsOH, Ba(OH)2, KOH

Weak bases;

NH3, (CH3)2NH, CH3NH2

A. KNO3

B. Ca(NO3)2

C. CaCl2

D. KCl

Explanation:

A strong acid/base is such an acid/base that dissociates completely in solution. This means that such acid/base achieves a nearly 100% ionization ability in solution.

A weak base or weak acid ionizes only to a small extent in solution.

The reaction between an acid and a base yields a salt. The corresponding salt in each of the reactions above were shown in the answer.

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mel-nik [20]
The first organisms are autotrophs (primary producers)
7 0
4 years ago
How many atoms are in 0.25 moles of carbon?
garik1379 [7]

Answer:

1.505535375e+23 or if it needs to be simple, 1.5.

Explanation:

Idk hope this helps.

4 0
3 years ago
A solution with a molarity of 0.1850 contains 19.30 grams of BaCl2. What is the volume of the solution
svetlana [45]

Answer:

Volume in L = 0.50 L

Explanation:

Given data:

Molarity of solution = 0.1850 M

Mass of BaCl₂ = 19.30 g

Volume of solution = ?

Solution:

First of all we will calculate the number of moles of solute:

Number of moles = mass/molar mass

Molar mass of BaCl₂ = 208.23 g/mol

Number of moles = 19.30 g / 208.23 g/mol

Number of moles = 0.093 mol

Volume of solution:

Molarity = number of moles of solute / volume of solution in L

0.1850 M = 0.093 mol / Volume in L

Volume in L = 0.093 mol / 0.1850 M  (M= mol/L)

Volume in L = 0.50 L

4 0
3 years ago
Calculate the mass (g) of 1.5 moles of Sulfur. ​
just olya [345]

Answer:

48 g S

Explanation:

Step 1: Define

Molar Mass of Sulfur (S) - 32.07 g/mol

Step 2: Use Dimensional Analysis

1.5 \hspace{3} mol \hspace{3} S(\frac{32.07 \hspace{3} g \hspace{3} S}{1 \hspace{3} mol \hspace{3} S} ) = 48.105 g S

Step 3: Simplify

We have 2 sig figs.

48.105 g S ≈ 48 g S

7 0
3 years ago
The energy required to start a reaction is called
V125BC [204]

Answer:

activation energy would be your answer here

Explanation:

4 0
3 years ago
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